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densk [106]
3 years ago
8

A monkey throws a banana peel from a height of 14 meters. It has a mass of 0.01 kilogram. What was the approximate potential ene

rgy of the banana peel before the monkey threw it?
Physics
1 answer:
liq [111]3 years ago
3 0
We need to use the equation for potencial energy

Ep= mgh

now we have to replace with the values we have

Ep=(14m)(9.81m/s²)(0.01kg)

Ep= 1.3734 Joules
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Friction robs some kinetic energy.

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8 0
3 years ago
A hot water heater is operated by using solar power. if the solar collector has an area of 5.3 m2 , and the power delivered by s
OLEGan [10]
Heat absorbed by the solar collector = Area*Irradiance = 5.3*995 = 5273.5 W

Heat Q in joules absorbed in t hours = Heat used to heat water. That is,

5273.5*t = mCΔT; where mass = volume*density = 1*1000 = 1000 kg

Therefore;
5273.5t = 1000*4186*(65-20) = 188370000
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4 0
3 years ago
A light with a second-order bright band forms a diffraction angle of 30.0°. The diffraction grating has 250.0 lines per mm. What
Simora [160]
I have no idea sorry
7 0
3 years ago
Read 2 more answers
An 4.0-kg fish pulled upward by a fisherman rises 1.9 m in 2.4 s, starting
mina [271]

Answer:

2.64N  

Explanation:

Force = mass * acceleration

Given

mass = 4kg

distance = 1.9m

Time t = 2.4s

Get the acceleration using the equation of motion

S = ut + 1/2at²

1.9 = 0 + 1/2a(2.4)²

1.9 = 5.76a/2

1.9 = 2.88a

a = 1.9/2.88

a = 0.66m/s²

Get the magnitude of the force

Force = 4 * 0.66

Force = 2.64N

Hence the net force acting on the fish is 2.64N  

5 0
3 years ago
Nellie pulls on a 10kg wagon with a constant horizontal force of 30N. If there are no other horizontal forces, what is the wagon
s2008m [1.1K]

Answer:

The acceleration of the wagon is 3 m/s².

To calculate the acceleration of the wagon, we use the formula below.

Formula:

F = ma............. Equation 1

Where:

F = horizontal Force

m = mass of the wagon

a = acceleration of the wagon.

make a the subject of the equation

a = F/m.............. Equation 2

From the question,

Given:

F = 30 N

m = 10 kg

Substitute these values into equation 2

a = 30/10

a = 3 m/s²

Hence, the acceleration of the wagon is 3 m/s².

5 0
2 years ago
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