To solve this problem we will apply the principle of conservation of energy. For this purpose, potential energy is equivalent to kinetic energy, and this clearly depends on the position of the body. In turn, we also note that the height traveled is twice that of the rigid rod, therefore applying these concepts we will have
Therefore the minimum speed at the bottom is required to make the ball go over the top of the circle is 4.67m/s
Answer:
Part a)
Part b)
Part C)
This is loss in terms of thermal energy due to collision with the floor
Explanation:
Part a)
Since we know that the ball rises up by 65% of initial height
so after first bounce it will lose 35% of its initial energy
so we will have
Energy Loss = 0.35 mgH[/tex]
Part b)
Energy of the ball after first bounce
energy of ball after 2nd Bounce
energy of the ball after 3rd bounce
Now we will have energy loss in fourth bounce given as
Part C)
This is loss in terms of thermal energy due to collision with the floor