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Tanya [424]
3 years ago
10

A hiker walks 15km due east then heads due north for 8km . What is the direction of the resultant vector?

Physics
1 answer:
4vir4ik [10]3 years ago
8 0

his displacements are given as

d_1 = 15 km East

d_2 = 8 km North

now we can find the direction of displacement by using the concept

\theta = tan^{-1}\frac{\deta y}{\delta x}

\theta = tan^{-1}\frac{8}{15}

\theta = 28.1 degree

magnitude of displacement is given as

d = \sqrt{x^2 + y^2}

d = \sqrt{15^2 + 8^2}

d= 17 km

<em>so the displacement is 17 km at angle 28.1 degree North of East</em>

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Answer:

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Explanation:

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3 years ago
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scoundrel [369]

Answer:

the light emitting must be of greater wavelength

Explanation:

For this exercise we must use the Planck equation

             E = h f

And the speed of light

            c = λ f

            f = c / λ

We replace

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The wavelength of the green light is of the order of 500 nm, let's calculate the energy

          E = 6.63 10⁻³⁴  3 10⁸ /λ

          E = 1,989 10⁻²⁵ /λ

          λ = 500 nm = 500 10⁻⁹ m

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That is the energy of the transition for a transition is an intermediate state the energy must be less, this implies that the wavelength must increase. For the explicit case of a state with half of this energy

            E_{int} = E / 2

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Let's clear and calculate

           λ = h c / E

           λ = 1,989 10⁻²⁵ / 1,989 10⁻¹⁹

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8 0
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In essence, they can be conductive or not under certain conditions.

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