Answer:
the smallest radius of the circular path is 8.1 km
Explanation:
The computation of the smallest radius of the circular path is given below:
Given that
V = Velocity = 201 m/s
a_c = acceleration = 5 m/s^2
radius = ?
As we know that
a_c = V^2 ÷ r
5 = 201^2 ÷ r
r = 201^2 ÷ 5
= 8,080.2 g
= 8.1 km
Hence, the smallest radius of the circular path is 8.1 km
Answer:
The equation of D = m/V
Where D = density
m = mass
and V = volume
We are solving for V, so with the manipulation of variables we multiply V on both sides giving us
V(D) = m
now we divide D on both sides giving us
V = m/D
We know our mass which is 600g and our density is 3.00 g/cm^3
so
V = 600g/3.00g/cm^3 = 200cm^3 or 200mL
a cubic centimeter (cm^3) is one of the units for volume. It's exactly like mL. 1 cm^3 = 1 mL
If you wish to change it to L, you'd have to convert
Explanation:
Tom used more Force but over a shorter distance. Tom and Claudia both did the same amount of work.
Answer:
a) frequency = 0.1724 Hz
b) Period = 5.8 sec
c) speed = 7.04 m/s
d) acceleration = 7.62 m/s²
Explanation:
Given that;
radius = 6.5m
time period = 5.8 sec every circle
a) the frequency
frequency is the number of rotation in unit time
frequency = 1 / time period = 1/5.8
frequency = 0.1724 Hz
b) the period
period is time taken in one rotation
period = total time / rotation = 5.8 / 1
Period = 5.8 sec
c) the speed
speed = distance/time = circumference/time period = 2πr / t = (2π×6.5) / 5.8
speed = 7.04 m/s
d) acceleration
To find the acceleration we take the linear velocity squared divided by the radius of the circle.
so
acceleration = v² / r = (7.04)² / 6.5 = 49.5616 / 6.5
acceleration = 7.62 m/s²
Vinyl records because it’s not a secure information storage
