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3 years ago

Volume of HCl used 25.0mL 4 l

Chemistry

1 answer:

borishaifa [10]3 years ago

8 0

Answer:

1.0 M

Explanation:

Reaction equation;

KOH(aq) + HCl(aq) -----> KCl(aq) + H2O(l)

Concentration of acid CA = ?

Concentration of base CB = 1.0 M

Volume of base VB = 25.60 - 0.50 = 25.1 ml

Volume of acid VB = 25.0 ml

Number of moles of acid NA = 1

Number of moles of base NB =2

CAVA/CBVB =NA/NB

CAVANB = CBVBNA

CA = CBVBNA/VANB

CA = 1 * 25.1 * 1/25.0 *1

CA = 1.0 M

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Answer:

C. Earth's revolution around the sun

Explanation:

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Read 2 more answers

What NaCl NaCl concentration results when 249 mL 249 mL of a 0.850 M 0.850 M NaCl NaCl solution is mixed with 667 mL 667 mL of a

tamaranim1 [39]

Answer:

The answer to your question is 0.54M

Explanation:

Data

Final concentration = ?

Concentration 1 = 0.850 M

Volume 1 = 249 ml = 0.249 l

Concentration 2 = 0.420 M

Volume 2 = 0.667 M

Process

1.- Calculate the number of moles in both solutions

Number of moles 1 = Molarity 1 x Volume 1

= 0.850 x 0.249

= 0.212

Number of moles 2 = Molarity 2 x Volume 2

= 0.420 x 0.667

= 0.280

Total number of moles = 0.212 + 0.280

= 0.492

2.-Calculate the final volume

Final volume = Volume 1 + Volume 2

Final volume = 0.249 + 0.667

= 0.916 l

3.- Calculate Molarity

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Molarity = 0.54

4 0

3 years ago

How many grams of NaCL are required to prepare 50ml of a 2.0 molar solution

Ksivusya [100]

Answer:

5.85 gm.

Explanation:

We know that,

Normality = Molarity × Molecular weight

Equivalent weight

Since molecular weight of NaCl= equivalent weight = 23+35.5 =58.5

Normality of NaCl= molarity=2

Now,

Normality= weight in gram ×1000

Volume ×equivalent weight

Weight in gram is given by,

=Normality × Volume × equivalent weight

1000

= 2× 50 × 58.5

1000

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3 years ago

a 5.00 L sample of helium expands to 12.0 L at which point the pressure is measured to be 0.720atm. what was the original pressu

stepan [7]

Answer:

The answer to your question is Pressure 1 = 1.73 atm

Explanation:

Data

Volume 1 = 5 l

Pressure 1 = ?

Volume 2 = 12 l

Pressure 2 = 0.72 atm

Process

To solve this problem use Boyle's law to solve this problem

Pressure 1 x Volume 1 = Pressure 2 x Volume 2

-Solve for Pressure 1

Pressure 1 = Pressure 2 x Volume 2 / Volume 1

-Substitutiion

Pressure 1 = 0.72 x 12 / 5

-Simplification

Pressure 1 = 8.64/5

-Result

Pressure 1 = 1.73 atm

5 0

3 years ago