With standard pressure there is a set list of values. (at STP), most common is 760torr. So whenever you see "at STP" or "at standard temperature pressure" you will use 760torr for pressure. Same thing goes with temperature, if you're not given temp and it says at STP you will use 273K.
For this problem:
You will be using the combined gas law:
(Pressure 1) x (Volume 1) / (Temp. 1) = (Pressure 2) x (Volume 2) / (Temp. 2)
(760torr) x (5.63L) / (287K) = (?) (9.21L) / (287K)
Pressure 2 = 465torr
*Hope this clarifies STP for you! :)
Answer:
OptionA. 2C4H10 + 13O2 —> 8CO2 + 10H20
Explanation:
Butane burns is air (O2) according to the equation:
C4H10 + O2 —> CO2 + H20
Considering the equation, it is evident that it not balanced. Now let us balance the equation as shown below;
There are a total of 4 carbon atoms on the left and 1 carbon atom on the right. It can be balanced by putting 4 in front of CO2 as shown below:
C4H10 + O2 —> 4CO2 + H20
Next, there are 10 hydrogen atoms on the left and 2 hydrogen atoms on the right. Therefore to balance it, put 5 in front of H2O as shown below:
C4H10 + O2 —> 4CO2 + 5H20
Now, there are a total of 13 oxygen atoms on the right and 2 at the left. To balance it, put 13/2 in front of O2
as shown below
C4H10 + 13/2O2 —> 4CO2 + 5H20
Now we multiply through by 2 clear off the fraction and we obtained:
2C4H10 + 13O2 —> 8CO2 + 10H20
Answer : The mass of oxygen will be, 36.8 grams
Solution : Given,
Moles of water = 2.30 moles
Molar mass of 
= 32 g/mole
First we have to calculate the moles of oxygen.
The balanced chemical reaction will be,
From the balanced reaction we conclude that
2 moles of water decomposes to give 1 mole of
2.30 moles of water decomposes to give 
moles of
Now we have to calculate the mass of oxygen.
Therefore, the mass of oxygen will be, 36.8 grams
Answer:1 is the answer i think
Answer:
4 mL
Explanation:
Use the density formula, d = m/v
Plug in the density and mass to solve for v:
4 = 16/v
4v = 16
v = 4
So, the volume is 4 mL
