Answer:
D
Explanation:
heat is an energy that transfers from a hot body to cold body
It is the acceleration of an object in free fall
Explanation:
When an object is in free fall, it is subjected only to one force: the force of gravity, which pulls the object downward, with a magnitude (near the Earth's surface) which is given by

where
m is the mass of the object
is the acceleration due to gravity
We can apply Newton's second law to the object in free fall:

where
F is the net force on the object
a is the acceleration of the object
m is the mass
However, since there is only the force of gravity acting on the object, the net force is equal to the force of gravity: so we can equate the two equations, obtaining that

Which means that the acceleration of an object in free fall (acted upon the force of gravity only) is equal to the acceleration due to gravity,
.
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Responder:
20.3 ° C
Explicación:
<u>Según la ley de Charles</u>: <em>cuando la presión sobre una muestra de gas seco se mantiene constante, la temperatura y el volumen estarán en proporción directa.
</em>
Paso uno:
datos dados
Temperatura T1 = 20 ° C
Temperatura T2 =?
Volumen V1 = 12.2 cm ^ 3
Volumen V2 = 12.4 cm ^ 3
Aplicar la relación temperatura y volumen

sustituyendo tenemos

Cruz multiplicar tenemos

Temperatura delle braci 20.3°C
Answer:

Explanation:
Take at look to the picture I attached you, using Kirchhoff's current law we get:

This is a separable first order differential equation, let's solve it step by step:
Express the equation this way:

integrate both sides, the left side will be integrated from an initial voltage v to a final voltage V, and the right side from an initial time 0 to a final time t:

Evaluating the integrals:

natural logarithm to both sides in order to isolate V:

Where the term RC is called time constant and is given by:

Answer:

Explanation:
Here two charges are placed at distance "d" apart
now the net value of electric field at some position between two charges will be ZERO
so we will have
electric field due to charge 1 = electric field due to charge 2

Let the position where net field is zero will lie at distance "r" from q1

now we will have

now square root both sides

now we have

so we have
