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SVEN [57.7K]
3 years ago
11

if you throw a 0.25-kg ball with a force of 20 n, what's the acceleration of the ball? a. 80 m/s2 b. 12.5 m/s2 c. 5 m/s2 d. 40 m

/s2
Physics
1 answer:
nata0808 [166]3 years ago
4 0
To answer this question, we can use Newton's Second Law:

F = ma

We know that:
F = 20N
m = 0.25kg

So, we can plug what we know into the equation and isolate for the acceleration.

20 = 0.25a

a = 80m/s^2 which corresponds to answer A
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On a straight horizontal track along which blocks can slide with negligible friction, block 1 slides toward block 2, which is in
vivado [14]

If the mass and post-collision speed of block 1 is known, the momentum of the block 2 can be determined.

<h3>What is momentum?</h3>

The momentum of an object in motion is the product of mass and speed of the object.

P = mv

<h3>Conservation of linear momentum</h3>

The principle of conservation of linear momentum states that, the sum of the initial momentum must be equal to the sum of the final momentum.

m_1v_1 = m_2 v_2

Thus, if the mass and post-collision speed of block 1 is known, the momentum of the block 2 can be determined.

Learn more about conservation of linear momentum here: brainly.com/question/7538238

7 0
2 years ago
A web page designer creates an animation in which a dot on a computer screen has a position of r⃗ =[ 4.50 cm +( 2.90 cm/s2 )t2]i
VMariaS [17]

Answer:

V = (5.8cm/s)i, (4.7cm/s)j

Explanation:

Given :

r⃗ =[ 4.50 cm +( 2.90 cm/s2 )t2]i^+( 4.70 cm/s )tj^

To obtain the average velocity (V)

V = (r2 - r1) / (t2 - t1)

To obtain r1 and r2, substitute t1 = 0 and t2 = 2 respectively in the equation above

r1 = [ 4.50 cm +( 2.90 cm/s2 ) 0]i^+( 4.70 cm/s )0 j

r1 = 4.50 cm + 0 + 0 = (4.50cm)i + 0j

r2 = [ 4.50 cm +( 2.90 cm/s2 )2²]i^+( 4.70 cm/s )2 j

r2 = 4.50cm + (2.90 × 4)i + (4.70 × 2)j

r2 = (16.1cm)i + (9.4cm)j

V = [(16.1 - 4.50)i - (9.4 - 0)j] / 2 - 0

V = 11.6i / 2 ; 9.4j / 2

V = (5.8cm/s)i, (4.7cm/s)j

5 0
3 years ago
When milk goes sour, what type of change has happened?
zzz [600]
B) Chemical change only
7 0
4 years ago
Read 2 more answers
A 75-hp (shaft output) motor that has an efficiency of 91.0 percent is worn out and is to be replaced by a high- efficiency moto
daser333 [38]

Convert the shaft ouput from HP to kW

Shaft output = 75HP = 55.93kW

 

1st: Finding for the power consumption based on 55.93kW output

Power consumption (Old) = 55.93kW / .910 = 61.46kW

Power consumption (New) = 55.93kW / .954 = 58.63kW

 

2nd: Total power used in kWh:

Power Used = Power consumption * load factor * Hours:

Power (Old) = 61.46kW * .75 * 4368 = 201343 kWh

Power (New) = 58.63kW * .75 * 4368 = 192072 kWh

Energy saved = 201343 kWh - 192072 kWh = 9,271 kWh

 

3rd: Calculating for the price:

Price = kW-Hr * $/kWh

Price (Old) = 201343kWh * $0.08/kWh = $16107.44

Price (New) = 192072 kWh * $0.08/kWh = $15365.76

Cost saved = $16107.44 - $15365.76 =  $741.68/yr

 

4th: Setting up the cost equation:

Cost over time, F(t) = Motor_Cost + (Price * Number of Years, t)

Cost (Old) = 5449 + 16107.44*t

Cost (New) = 5520 + 15365.76*t

Equate the two to find for t when they cost equally:

5449 + 16107.44*t = 5520 + 15365.76*t

16107.44*t = 15365.76*t +71

16107.44*t - 15365.76*t = 71

741.68*t = 71

t = 71 / 741.68 = .095 years = 35 days

So the payback period is after 35 days.

6 0
3 years ago
Convert 9/4 hours into minutes
Eduardwww [97]

Am guessing;

9/4 × 60/1 =135

5 0
3 years ago
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