The banking angle of the curved part of the speedway is determined as 32⁰.
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Banking angle of the curved road</h3>
The banking angle of the curved part of the speedway is calculated as follows;
V(max) = √(rg tanθ)
where;
- r is radius of the path
- g is acceleration due to gravity
V² = rg tanθ
tanθ = V²/rg
tanθ = (34²)/(190 x 9.8)
tanθ = 0.62
θ = arc tan(0.62)
θ = 31.8
θ ≈ 32⁰
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Answer:
The water turns in to vapor and rises in the air leaving the salt behind
Explanation:
Answer:
Explanation:
= Charge at 3000 m = 40 C
= Charge at 1000 m = -40 C
= 3000 m
= 1000 m
k = Coulomb constant = 
Electric field due to the charge at 3000 m
Electric field due to the charge at 1000 m
Electric field at the aircraft is 
.
Answer:
500ms times 2 would be when the ball reaches the max horizontal distance.
Then to find the angle, use the formula of time to reach max height t = u sin theta / g . With t being the max height time 500ms, u being 10m/s
For initial vertical velocity just use u sin theta.
