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Serga [27]
2 years ago
10

A boy 11.0 m above the ground in a tree throws a ball for his dog, who is standing right below the tree and starts running the i

nstant the ball is thrown. If the boy throws the ball upward at 50.0 ∘ above the horizontal, at 8.00 m/s .
How fast must the dog run to catch the ball just as it reaches the ground?
How far from the tree will the dog catch the ball?
Physics
1 answer:
ryzh [129]2 years ago
8 0

12414253

Explanation:

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A ball rolls of buildings that is 100m high calculate the time that it takes for ball to hit the ground​
LUCKY_DIMON [66]

Answer:

2as=v2-u2

2000=v2

V=44

V=u+at

44/10=t

T=4.4seconds

5 0
3 years ago
A house is lifted from its foundations onto a truck for relocation. The house is pulled upward by a net force of 2850 N. This fo
Gwar [14]

Answer:

m = 95000 kg

Explanation:

Given that,

Net force acting on the house, F = 2850 N

Initial speed, u = 0

Final speed, v = 15 cm/s = 0.15 m/s

We need to find the mass of the house. Let the mass be m. We know that the net force is given by :

F = ma

Where

a is the acceleration of the house.

So,

F=m\dfrac{v-u}{t}\\\\m=\dfrac{Ft}{(v-u)}\\\\m=\dfrac{2850\times 5}{(0.15-0)}\\\\m=95000\ kg

So, the mass of the house is equal to 95000 kg.

3 0
2 years ago
What is the difference between kinetic energy and potential energy​
uranmaximum [27]

Answer:

Kinetic energy is the energy of a moving body while potential energy is the energy by vutue of it's position

8 0
3 years ago
What is electricity?
ASHA 777 [7]

Answer:

The flow of electric charge

Explanation:

Electricity:It is defined flow of electric charge.

It is defined as the flow of charge per unit time.

Electric charge can be negative or positive .

Mathematical representation :

If charge Q flowing through the conductor and time taken in flow of charge is t seconds.

Then, current=I=\frac{Q}{t}

S.I unit of current is Ampere.It is scalar quantity.

Answer:The flow of electric charge.

8 0
3 years ago
At what distance along the central perpendicular axis of a uniformly charged plastic disk of radius 0.390 m is the magnitude of
aliina [53]
<span>Radius, the distance from the centre = 0.390
 Electric field is equal to half of the magnitude. E2 = E / 2
 Given
E1 = E2 E1 = k x Q / r^2
  E2 = (k x Q / r2^2) / 2
  Equating the both we get 2 x r^2 = r2^2
 r2 = square root of (2 x r1^2) = square root of (2) x r = 1.414 x 0.390
  r2 = 1.414 x 0.390 = 0.551 m</span>
3 0
2 years ago
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