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insens350 [35]
4 years ago
12

As the particles of a solid undergo sublimation , they?

Chemistry
1 answer:
vladimir2022 [97]4 years ago
4 0
They are particular solids.
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Which is the pathway of light as it travels through the eye?cornea → iris → retina → lenscornea → iris → lens → retinairis → cor
Vikki [24]

Answer:

Cornea >iris>lens >retina

Explanation:

Can't exactly figure out the answer but I think it should look like this

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2 years ago
How many atoms of carbon are present in a molecule of :<br> Fructose and galactose
nasty-shy [4]
In Fructose, there are 4 carbon atoms. Fructose is a 5 atom molecule, and one of these is oxygen, therefore, the other 4 are carbon.
In Galactose, there are 6 carbon atoms.
Hope this helps :) 
6 0
3 years ago
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What is the wavelength of the line corresponding to n=4 in the balmer series? express your answer in nanometers to three signifi
liq [111]
Expression for the Balmer series to find the wavelength of the spectral line is as follows:
1 / λ = R (\frac{1}{2^{2} } -  \frac{1}{ n^{2}} )
Where, λ is wavelength, R is Rydberg constant, and n is integral value (4 here →  Fourth level) 
Substitute 1.097 x 10⁷ m⁻¹ for R and 4 for n in the above equation 
1 / λ = (1.097 x 10⁷ m⁻¹) (\frac{1}{2^{2} } -  \frac{1}{4^{2} }  ) 
   = 0.20568 x 10⁷ m⁻¹
λ = 4.86 x 10⁻⁷ m 
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8 0
3 years ago
Two diseases wiped out by vaccines are what and what
Olenka [21]
One of the diseases is smallpox and the second is rinderpest
3 0
2 years ago
One gram of liquid benzene is burned in a bomb calorimeter. The temperature before ignition was 20.826 ℃, and the temperature af
gtnhenbr [62]

Answer:fH = - 3,255.7 kJ/mol

Explanation:Because the bomb calorimeter is adiabatic (q =0), there'is no heat inside or outside it, so the heat flow from the combustion plus the heat flow of the system (bomb, water, and the contents) must be 0.

Qsystem + Qcombustion = 0

Qsystem = heat capacity*ΔT

10000*(25.000 - 20.826) + Qc = 0

Qcombustion = - 41,740 J = - 41.74 kJ

So, the enthaply of formation of benzene (fH) at 298.15 K (25.000 ºC) is the heat of the combustion, divided by the number of moles of it. The molar mass od benzene is: 6x12 g/mol of C + 6x1 g/mol of H = 78 g/mol, and:

n = mass/molar mass = 1/ 78

n = 0.01282 mol

fH = -41.74/0.01282

fH = - 3,255.7 kJ/mol

4 0
3 years ago
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