Water (2510 g ) is heated until it just begins to boil. if the water absorbs 5.01×105 j of heat in the process, what was the ini tial temperature of the water?\
1 answer:
E=energy=5.09x10^5J = 509KJ <span>M=mass=2250g=2.25Kg </span> <span>C=specific heat capacity of water= 4.18KJ/Kg </span> <span>ΔT= change in temp= ? </span> <span>E=mcΔT </span> <span>509=(2.25)x(4.18)xΔT </span> <span>509=9.405ΔT </span> <span>ΔT=509/9.405=54.1degrees </span> <span>Initial temp = 100-54 = 46 degrees </span> <span>Hope this helps :)</span>
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