Answer:
a) E = 7.57 10⁻⁵ N / C, b) B= 2.11 10⁻¹⁸ T, c) the magnitudes remain the same, but the sign of the responses change
Explanation:
a) The electric field due to a charged particle is
E = k q / r²
Let's look for the distance from the origin where the particle is to the point of interest
r² = (-3 10⁻³ -0)² + (-3 10⁻³ -0)²
r² = 19 10⁻⁶
The proton charge is
q = +1.6 10⁻¹⁹ C
Let's calculate
E = 8,988 10⁹ 1.6 10⁻¹⁹ / 19 10⁻⁶
E = 7.57 10⁻⁵ N / C
b) to calculate the magnetic field let's use the Biot-Savat law
B = μ₀/4π I / r²
The current is defined as the number of carriers per unit of time at a given point
I = q v
Let's calculate
B = 4π 10⁻⁷ /4π (1.6 10⁻¹⁹ 4 10⁴) / 19 10⁻⁶
B= 2.11 10⁻¹⁸ T
c) an electron has a charge of the same magnitude, but in the opposite direction, negative.
Therefore the magnitudes remain the same, but the senses (sign) of the responses change