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GREYUIT [131]
3 years ago
9

In your discussion post, think about some examples of exponential growth in the real world. They might be examples from science,

medicine, or finances. Share two examples of exponential growth, and include a description of who would benefit from the information found in these examples. Also include, two examples of careers and jobs that would be difficult to work in if you didn't understand exponential growth. Describe why it would be difficult in these specific examples.
Business
1 answer:
Stels [109]3 years ago
3 0

Answer: interest and population growth

Explanation:

Examples of exponential growth in real world.

1. interest on a savings account (finance). example when you deposit let say $1000 in an account that earns you a simple interest rate of 10% in a year you would earn $100, with each year the amount of interest paid continues to grow exponentially. The bank customer or owner of the account stands to benefit from this growth.

2. Population growth ( science ) population continues to grow exponentially overtime due to individuals available to produce not minding the available resources.a large population usually translates to a good economy development due to more people available so the citizen benefits from it.

Examples of career that it would be difficult to work in

1. Financial advisor

2. Bankers

For someone working as a financial advisor or banker would need the knowledge of exponential growth by understanding compound returns. In finance, compound returns leads to exponential growth. Compounding powers is part the most powerful tools in finance. This method is used by financial advisors and bankers for creating large sums from an initial deposit.

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One advantage of free trade is: Group of answer choices advanced production operations are built in low-wage countries. innovati
marshall27 [118]

Answer:

Innovation for new products occurs which keeps firms competitively challenged

Explanation:

Free trade can be regarded as a

theoretical policy , that governments use when there is no imposition of

tariffs/taxes, as well as duties on imports as well as exports.

free trade can be regarded as the opposite of protectionism. It should be noted that One advantage of free trade is Innovation for new products occurs which keeps firms competitively

7 0
3 years ago
Assume your computer is able to complete 4 double floating-point operations per cycle when operands are in registers and it take
svp [43]

Answer:

<em>For 1st algorithm</em><em>: The total run time is 200.25 s, while that of total waste time is 200 sec and the percentage of the waste time is 99.8%.</em>

<em>For 2nd algorithm:</em><em>The total run time is 100.35 s, while that of total waste time is 100.1 sec and the percentage of the waste time is 99.75%.</em>

Explanation:

As the complete question is not visible, therefore, the question is searched online and following reference question is obtained.

Following data is given as

Floating point operation time=T/4

Memory Access Time =100T

Frequency =2 GHz

Number of Cycles=1000

<u>1st Algorithm</u>

<em>/*dgemm0: simple ijk version triple loop</em>

<em>algorithm*/</em>

<em>for (i=0; i<n; i++)</em>

<em>for (j=0; j<n; j++)</em>

<em>for (k=0; k<n; k++)</em>

<em>c[i*n+j] += a[i*n+k] * b[k*n+j];</em>

First by rewriting the operation inside the inner loop:

= + ×

Now first A, B and C are loaded into the registers so

Load \,Time=3 \times Memory \,Access \,Time=3 \times 100\, T =300\, T

For 2 floating point computations (addition and multiplication)

Computation\, Time=2 \times Floating\, Time\\Computation\, Time=2 \times \frac{T}{4}\\Computation\, Time=\frac{T}{2}

Finally, to store and repeat the cycle as N^3 times the time is estimated as

Store \,Time=Memory\, Access\, Time=100T

Total Run time is given as

T_{run}=N^3 \times [T_{load}+T_{comp}+T_{store}]\\T_{run}=1000^3 \times [300T+\frac{T}{2}+100T]\\T_{run}=1000^3 \times [400.5T]\\T_{run}=200.25 s

Total Wasted time is given as

T_{waste}=N^3 \times [T_{load}+T_{store}]\\T_{waste}=1000^3 \times [300T+100T]\\T_{waste}=1000^3 \times [400T]\\T_{waste}=200 s

Percentage of Waste time is given as

\%age \, waste=\frac{T_{waste}}{T_{run}}\times 100\\\%age \, waste=\frac{200}{200.25}\times 100\\\%age \, waste=99.8\%

<em>The total run time is 200.25 s, while that of total waste time is 200 sec and the percentage of the waste time is 99.8%.</em>

<u>2nd Algorithm</u>

<em>/*dgemm1: simple ijk version triple loop</em>

<em>algorithm with register reuse*/</em>

<em>for (i=0; i<n; i++)</em>

<em>for (j=0; j<n; j++) {</em>

<em>register double r = c[i*n+j];</em>

<em>for (k=0; k<n; k++)</em>

<em>r += a[i*n+k] * b[k*n+j];</em>

<em>c[i*n+j] = r;</em>

<em>}</em>

Initialize register r with the content of C for N2 Times as given as Initialization\,Time=N^2 \times Memory \,Access \,Time=N^3 \times 100\, T

Time for Loading Operands A and B into registers for N3 Times is given as

Load \,Time=N^3 \times 2 \times Memory \,Access \,Time=N^3\times 2 \times 100\, T =N^3\times 200\, T

For 2 floating point computations (addition and multiplication)

Computation\, Time=N^3 \times\frac{T}{2}

Final Memory update to store result in the register r to the memory for N2 Times

Store \,Time=Memory\, Access\, Time=N^2 \times 100T

Total Run time is given as

T_{run}=N^3 \times [T_{load}+T_{comp}]+N^2 \times [T_{linit}+T_{store}]\\T_{run}=1000^3 \times [200T+\frac{T}{2}]+1000^2 \times [100T+100T]\\T_{run}=1000^3 \times [200.5T]+1000^2 \times [200T]\\T_{run}=100.35 s

Total Wasted time is given as

T_{waste}=N^3 \times [T_{load}]+N^2 \times [T_{init}+T_{store}]\\T_{waste}=1000^3 \times [200]+1000^2 \times [100T+100T]\\T_{waste}=1000^3 \times [200T]+1000^2 \times [200T]\\T_{waste}=100.1 s

Percentage of Waste time is given as

\%age \, waste=\frac{T_{waste}}{T_{run}}\times 100\\\%age \, waste=\frac{100.1}{100.35}\times 100\\\%age \, waste=99.75\%

<em>The total run time is 100.35 s, while that of total waste time is 100.1 sec and the percentage of the waste time is 99.75%.</em>

8 0
3 years ago
Several advocacy groups in the U.S. monitor firms that do business with sweatshops in developing nations. These watchdog groups
Dmitry_Shevchenko [17]

Answer:

The answer is: C) safety needs

Explanation:

According to Maslow safety and security needs are about keeping us safe. In this case, the factories that operate in developing nations offer their employees job security. This is very important for those employees since the alternative to working in those factories would be probably unemployment or jobs that pay even less or over even worse working conditions.  

3 0
4 years ago
Quark Inc. just began business and made the following four inventory purchases in June: June 1 150 units $ 825 June 10 200 units
HACTEHA [7]

Answer:

$1,170

Explanation:

The amount allocated to ending inventory for June using FIFO inventory method is computed as;

= $885 + [($1,140 ÷ 200) × (200 - 150]

= $88 5 + ($5.7 × 50)

= $885 + $285

= $1,170

6 0
3 years ago
You and several classmates are studying for the next accounting examination. They ask you to answer the following questions: (Ro
Flauer [41]

Answer:

Sry that i could answer the question but i hope u have a great day.

Explanation:

8 0
3 years ago
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