1. A mixture of ammonium chloride, sand, and zinc chloride should be separated by sublimation.
2. A mixture of zinc chloride and silver chloride should be separated through crystallization.
<h3>What is a separation technique?</h3>
A separation technique can be defined as a technique that is typically used to separate or convert two (2) or more mixture and solution of chemical substances into distinct product such as chemical compounds or elements.
<h3>The types of
separation technique.</h3>
In Chemistry, there are various types of separation technique used for the separation of mixtures or solutions and these include:
In this scenario, the most effective and efficient means to separate a mixture of ammonium chloride, sand, and zinc chloride is by sublimation from solid to gas state.
On the other hand, the best means to separate a mixture of zinc chloride and silver chloride is through crystallization.
Read more on crystallization here: brainly.com/question/4980962
Answer:
When hydrogen gas combines with nitrogen to form Ammonia the following chemical reaction will take place. Our equilibrium reaction will be N2(g) + 3H2(g) ⇔ 2NH3(g) + Heat. In this case, Hydrogen and nitrogen react together to form ammonia.
Explanation:
The answer is (3). The number of Sr is the same so if the compound has the smallest gram formula mass, it has the highest percent composition by mass of strontium. So the answer is (3).
Answer : The enthalpy change for the process is 52.5 kJ/mole.
Explanation :
Heat released by the reaction = Heat absorbed by the calorimeter + Heat absorbed by the solution
![q=[q_1+q_2]](https://tex.z-dn.net/?f=q%3D%5Bq_1%2Bq_2%5D)
![q=[c_1\times \Delta T+m_2\times c_2\times \Delta T]](https://tex.z-dn.net/?f=q%3D%5Bc_1%5Ctimes%20%5CDelta%20T%2Bm_2%5Ctimes%20c_2%5Ctimes%20%5CDelta%20T%5D)
where,
q = heat released by the reaction
= heat absorbed by the calorimeter
= heat absorbed by the solution
= specific heat of calorimeter = 
= specific heat of water = 
= mass of water or solution = 
= change in temperature = 
Now put all the given values in the above formula, we get:
![q=[(12.1J/^oC\times 6.1^oC)+(100.0g\times 4.18J/g^oC\times 6.1^oC)]](https://tex.z-dn.net/?f=q%3D%5B%2812.1J%2F%5EoC%5Ctimes%206.1%5EoC%29%2B%28100.0g%5Ctimes%204.18J%2Fg%5EoC%5Ctimes%206.1%5EoC%29%5D)
Now we have to calculate the enthalpy change for the process.
where,
= enthalpy change = ?
q = heat released = 2626.61 J
n = number of moles of copper sulfate used = 
Therefore, the enthalpy change for the process is 52.5 kJ/mole.
