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densk [106]
2 years ago
7

PHYSICS QUESTION - CAN ANYONE HELP NOW?

Physics
2 answers:
Brums [2.3K]2 years ago
6 0

Givens: m=20kg r=2.0m L=360 kg m^2/s

Unknown: Speed . (But there are two "types of speed" which are angular speed and linear speed and ARE DIFFERENT)

Formulas: L=Iω  Angular momentum = inertia x angular velocity (L=Iω)

I=mr^2; ω=v/r  

Therefore, L=r^2m * v/r = rmv


L=rmv

360=20*2*v

360/(20*2) =v

360/40= v

v=9m/s (linear tangent speed)  

Angular velocity ω= v/r  

ω= 9/2

ω= 4.5rads/s (angular speed)


In other words, both 9 and 4.5 should be right if explained correctly.

GrogVix [38]2 years ago
3 0
It's velocity when it strikes the ground is. D. 232.9 kg.m/s<span>.
</span>
I hope this helps!!!







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Do you think the plan for the skyscraper in California is appropriate based on its location? Why or why not? Your answer should
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No

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5 0
3 years ago
WOULUJUTUL RECIPECUIUS.
3241004551 [841]

The force between the two objects is 19.73 nN.

<u>Explanation: </u>

Any force acting between two objects tends to be directly proportional to the product of their masses and inversely proportional to the square of the distance between the two objects. And this kind of attraction force between two objects is termed as gravitational force.

So if we consider M_{1} and M_{2} as the masses of both objects and let d be the distance of separation of two objects. Then the force between the two objects can be determined as below:

                      \text {Gravitational force}=\frac{G \times M_{1} \times M_{2}}{d^{2}}

As gravitational constant G=6.67 \times 10^{-11} \mathrm{m}^{3} \mathrm{kg}^{-1} \mathrm{s}^{-2}, M_{1} = 20 kg and  M_{2} = 100 kg, while d = 2.6 m, then

                    \text {Gravitational force}=\frac{6.67 \times 10^{-11} \times 20 \times 100}{(2.6)^{2}}=\frac{6.67 \times 20 \times 10^{-9}}{6.76}

Thus, we get finally,

                   \text {Gravitational force}=19.73 \times 10^{-9} \mathrm{N}

As we know, nano denoted by letter 'n' equals to 10^{-9}

So the force acting between two objects is 19.73 nN.

7 0
2 years ago
If a wave is traveling at 60cm/second and has a wavelength of 15 cm what is the frequency?
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The greater the of an object the more force is needed to cause acceleration
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the greater the <u>mass</u> of an object the more force is needed to cause acceleration



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3 years ago
A piano emits frequencies the range from a low of about 28 Hz to a high of about 4200 Hz. Find the range of wavelengths in air a
Step2247 [10]
V=wave velocity , <span>f= frequency, </span><span>λ=wavelength </span>
<span>Use it to find corresponding wavelengths for</span><span> f=28 Hz </span>
<span>λ= v/f= 337/28=12.036 m 
</span>
<span>for f=4200 Hz </span>
<span>λ= v/f=337/4200= 0.08 m </span>
<span>So max. wavelength is 12.036 m and </span>
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4 0
3 years ago
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