Question

2. Find the electrostatic force between two protons that are 2.0 m apart. The elementary charge of

Answer 1

Answer:

the electrostatic force between the two protons is 5.775 x 10⁻²⁹ N.

Explanation:

Given;

charge of protons, q = 1.602 x 10⁻¹⁹ C

distance between the two charges, r = 2.0 m

The electrostatic force between the two protons is calculated as;

$F = \frac{kq^2}{r^2}$

where;

k is coulomb's constant, = 9 x 10⁹ Nm²/C²

$F = \frac{(9\times 10^9)(1.602 \times 10^{-19})^2}{(2)^2} \\\\F = 5.775 \times 10^{-29} \ N$

Therefore, the electrostatic force between the two protons is 5.775 x 10⁻²⁹ N.