Answer:
The correct answer is option 'c': Smaller stone rebounds while as larger stone remains stationary.
Explanation:
Let the velocity and the mass of the smaller stone be 'm' and 'v' respectively
and the mass of big rock be 'M'
Initial momentum of the system equals

Now let after the collision the small stone move with a velocity v' and the big roch move with a velocity V'
Thus the final momentum of the system is 

Equating initial and the final momenta we get

Now since the surface is frictionless thus the energy is also conserved thus 

Similarly the final energy becomes
 \
\
Equating initial and final energies we get

Solving i and ii we get

Using this in equation i we get
 
 
Thus putting v = -v' in equation i  we get V' = 0
This implies Smaller stone rebounds while as larger stone remains stationary.
 
        
             
        
        
        
 
 in the service producing sector
 
 
        
             
        
        
        
Answer:
the force of the plow pulling backward on the tractor
Explanation: