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crimeas [40]
3 years ago
15

What will happen to the chemical equilibrium if MgCl2 is added?

Chemistry
1 answer:
Verizon [17]3 years ago
6 0
The chemical equilibrium will be unaffected 
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PLEASE HELP! I DONT UNDERSTAND WHAT TO DO!
goldenfox [79]

Answer:

Na+Cl- + Ag+no3- ---> Na+No3- + Ag+Cl-

A spectator ion is an ion that exists as a reactant and a product in a chemical equation

Explanation:

When a solution of sodium hydroxide, NaOH, is mixed with hydrochloric acid, HCl, the compounds dissociate into the ions Na+, OH-, H+ and Cl-. The hydrogen and hydroxide ions react to form water, but the sodium and chlorine ions stay in solution unchanged.

5 0
3 years ago
T’Keyah puts salt in ice water and then in boiling water to see which will dissolve faster.Which dissolving rate factor is she t
WARRIOR [948]

Answer:

temperature

Explanation:

its in the book

8 0
2 years ago
Read 2 more answers
An environmental scientist developed a new analytical method for the determination of cadmium (cd^2+) in mussels. To validate th
Anettt [7]

Answer:

The method is accurate  in the calculation of the Cu^+2

Explanation:

As a first step we have to calculate the <u>average concentration </u>of Cu^+2 find it by the method.

\frac{0.782+0.762+0.825+0.838+0.761 }{5} =0.79 ppm

Then we have to find the<u> standard deviation:</u>

s=\sqrt{\frac{1}{N-1}\sum_{i=1}^N(x_i-\bar{x})^2}=0.0359

For the confidence interval we have to use the formula:

μ=Average±\frac{t*s}{\sqrt{n} }

Where:

t=t student constant with 95 % of confidence and 5 data=2.78

μ= 0.79  ±  \frac{2.78*0.0359}{\sqrt{5} }

upper limit:  0.84

lower limit: 0.75

If we compare the limits of the value obtanied by the method (Figure 1 Red line) with the reference material (Figure 1 blue line) we can see that the values obtained by the method are within the values suggested by the reference material. So, it's method is accurate.

7 0
3 years ago
Can you help me understand this question
snow_tiger [21]
You should talk about how it evaporates then it turn into a gas then back in to a liquid
6 0
3 years ago
How many moles of Na2SO4 can be made with 7.28 mol of H2SO4?
Slav-nsk [51]

Answer:

7.28 mol Na2SO4

Explanation:

Since it is already in moles, all we have to do is use a molar ratio

A molar ratio is the proportions of reactants and products using the balanced equation. When writing a mole ratio, the given information must cross out with the right thing.

7.28 mol H2SO4 * 1 mol Na2SO4/1 H2SO4 = 7.28 mol Na2SO4

*notice how the H2SO4 crosses out

5 0
3 years ago
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