Answer: a) The acceletarion is directed to the center on the turntable. b) 5 cm; ac= 0.59 m/s^2; 10 cm, ac=1.20 m/s^2; 14 cm, ac=1.66 m/s^2
Explanation: In order to explain this problem we have to consider teh expression of the centripetal accelartion for a circular movement, which is given by:
ac=ω^2*r where ω and r are the angular speed and teh radios of the circular movement.
w=2*π*f
We know that the turntable is set to 33 1/3 rev/m so
the frequency 33.33/60=0.55 Hz
then w=2*π*0.55=3.45 rad/s
Finally the centripetal acceleration at differents radii results equal:
r= 0.05 m ac=3.45^2*0.05=0.50 m/s^2
r=0.1 ac=3.45^2*0.1=1.20 m/s^2
r=0.14 ac=3.45^2*0.14=1.66 m/s^2
Answer:
The initial current, Io = 2.06×10^-4A
Explanation:
The I itial current ,Io of a circuit is given by:
Io = Vo/R
Where Vo = initial votage
R = resistance in ohms
Given:
Vo = 1.50V
R = 7290ohms
Io = 1.50/ 7290
Io = 2.06 ×10^-4A
Answer:
a) F₁ = F₂, F₃ = F₄, b) the correct answer is 3
Explanation:
a) In this exercise we have several action and reaction forces, which are characterized by having the same magnitude, but different direction and being applied to different bodies
Forces 1 and 2 are action and reaction forces F₁ = F₂
Forces 3 and 4 are action and reaction forces F₃ = F₄
as it indicates that the
b) how the car increases if speed implies that force 1> force3
F₁ > F₃
therefore the correct answer is 3
Answer:
P=mv 2250*25=56250
Explanation:
p of truck =2250*25 =56250
since p of truck = p of car
then p of car = 56250
therefore p of car = 1210 * v
or, 56520=1210v
or,v= 56520/1210=46.48
so, v of car is 46.48m/s
Answer: impulse and momentum
Explanation:
