All categories

2 years ago

Resolve the weight of the box to find the component of the weight acting parallel to the slope.

Physics

1 answer:

tekilochka [14]2 years ago

4 0

Answer:

here's your answer below

Explanation:

sorry something went wrong

You might be interested in

Which biome is most likely to have animals that hibernate, or sleep for long periods during the winter to avoid the cold?

TiliK225 [7]

Either tundra or polar i think.

5 0

3 years ago

Read 2 more answers

What is the output voltage from a step up transformer with 25 turns in the primary coil and 75 turns in the secondary coil if th

Greeley [361]

Answer:

360 V

Explanation:

We can use the transformer equation:

$\frac{V_p}{N_p}=\frac{V_s}{N_s}$

where

$V_p$ is the primary (input) voltage

$N_p$ is the number of turns in the primary coil

$V_s$ is the secondary (output) voltage

$N_s$ is the number of turns in the secondary coil

In this problem,

$V_p = 120 V\\N_p = 25\\N_s = 75$

Substituting into the equation, we can find the output voltage:

$V_s = N_s \frac{V_p}{N_p}=(75)\frac{120}{25}=360 V$

7 0

3 years ago

A 0.5 m diameter wagon wheel consists of a thin rim having a mass of 7 kg and six spokes, each with a mass of 1.2 kg. 1.2 kg 7 k

Arte-miy333 [17]

Explanation:

It is given that,

Mass of the rim of wheel, m₁ = 7 kg

Mass of one spoke, m₂ = 1.2 kg

Diameter of the wagon, d = 0.5 m

Radius of the wagon, r = 0.25 m

Let I is the the moment of inertia of the wagon wheel for rotation about its axis.

We know that the moment of inertia of the ring is given by :

$I_1=m_1r^2$

$I_1=7\times (0.25)^2=0.437\ kgm^2$

The moment of inertia of the rod about one end is given by :

$I_2=\dfrac{m_2l^2}{3}$

l = r

$I_2=\dfrac{m_2r^2}{3}$

$I_2=\dfrac{1.2\times (0.25)^2}{3}=0.025\ kgm^2$

For 6 spokes, $I_2=0.025\times 6=0.15\ kgm^2$

So, the net moment of inertia of the wagon is :

$I=I_1+I_2$

$I=0.437+0.15=0.587\ kgm^2$

So, the moment of inertia of the wagon wheel for rotation about its axis is $0.587\ kgm^2$ . Hence, this is the required solution.

4 0

3 years ago

You have 0.5 l of air at a pressure of 203 kpa and -70°c in a rigid, sealed contaainer. what is the absolute tempertaure of the

ANTONII [103]

From the information given and if the question is complete then;
Absolute temperature is the temperature in Kelvin
To convert degree Celsius to kelvin we normally add 273
that is Kelvin = deg Celsius + 273
Thus since we have been given that the air was at -70 degrees celcius;
then; - 70° C + 273 = 203 K
Therefore; the absolute temperature is 203 K

5 0

3 years ago

How can global climate change be studied

Marina CMI [18]

Not sure... need help with it

4 0

3 years ago