Question

A person wax walk at 1m/sand then accelerate at 2 m/s^2 for 2 seconds

Answer 1

Answer:

The person is moving at 5 meters per second (m/s)

The person has traveled 6 meters

Explanation:

This is an example of accelerated motion (motion under acceleration), and therefore we need to use the appropriate equations of motion for it.

The information we have includes:

1) The initial velocity ($v_i$) of the person = 1 m/s

2) The person's acceleration ($a$) = 2 $m/s^2$

3) The time (t) the person moves under accelerated motion = 2 seconds

The following two equations are those to find the final velocity under accelerated motion, and the distance covered (from initial position $x_i$ to final position $x_i$) under accelerated motion:

$v_f=v_i+a*t\\x_f-x_i=v_i*t+\frac{1}{2} a*t^2$

We use the first equation and the information given, to find the speed of the person after 2 second under this motion:$v_f=v_i+a*t\\v_f=1\frac{m}{s} +2\frac{m}{s^2} * 2s=(1+4)\frac{m}{s} = 5\frac{m}{s}$

We use the second formula to find the distance traveled by the person:

$x_f-x_i=v_i*t+\frac{1}{2} a*t^2\\distance=1\frac{m}{s} * 2s+\frac{1}{2} 2*\frac{m}{s^2}*(2s)^2\\distance=2m+4m=6m$