Answer:
6.24 x 10-3 M
Explanation:
Hello,
In this case, for the given dissociation, we have the following equilibrium expression in terms of the law of mass action:
![Ka=\frac{[H_3O^+][BrO^-]}{[HBrO]}](https://tex.z-dn.net/?f=Ka%3D%5Cfrac%7B%5BH_3O%5E%2B%5D%5BBrO%5E-%5D%7D%7B%5BHBrO%5D%7D)
Of course, water is excluded as it is liquid and the concentration of aqueous species should be considered only. In such a way, in terms of the change 
, we rewrite the expression considering an ICE table and the initial concentration of HBrO that is 0.749 M:
Thus, we obtain a quadratic equation whose solution is:
Clearly, the solution is 0.00624 M as no negative concentrations are allowed, so the concentration of BrO⁻ is 6.24 x 10-3 M.
Best regards.
1. transformation
2. transfer
3. transformation
4. transfer
not 100% but hope it helped kinda
Answer:
a. 2257.7 kW b. 6.057kw/K
Explanation:
Steam existing at 100KPa with t = 20C, we can obtain values of enthalpy and entropy from table
h1 = hf = 417.4 kJ/kg
s1 = 1.302 KJ/kg.K
h2 = hg = 2675.1 kJ/kg
s2 = 7.359 kJ/K
a. Electrical Power consumption of system is given by Wel = mass x Change in Enthalpy
Wel = 1 x (h2 - h1) = 1 x (2675.1 - 417.4) = 2257.7 kw
b . Entropy Generation is given by Change in Entropy = Entropy generation - heat dissipated/temperature, since we have a well insulated system with no losses, q =0, hence
ΔS = Sgen + 0/T = Sgen
m(S2 - S1) = Sgen
Sgen = 1 x (7.359 - 1.302) = 6.057 kW/K
Answer:
well it is because of mainly what we call reaction the petrol are highly reactive with the flames
Answer:
In physics, action is an attribute of the dynamics of a physical system from which the equations of motion of the system can be derived through the principle of stationary action. ... Action has dimensions of energy⋅time or momentum⋅length, and its SI unit is joule-second.
Explanation:
hope it helps
