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3 years ago

What is the expanded and word form for 67.943

Mathematics

1 answer:

adell [148]3 years ago

8 0

Word : Sixty-Seven and Nine Hundred Forty-Three Thousandths
Expanded : 60 + 7 + 0.9 + 0.04 + 0.003

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Someone please answer this for me!!! Its 1 Answer !!!

Nikolay [14]

Answer:

8.69 × 10^4

For a clearer answer look at the image.

Step-by-step explanation:

10² + 10² = 10^4

5.84 + 2.85 = 8.69

8.69 × 10^4

5 0

3 years ago

Maddie biked 8 3/4 miles today, and Chase bikes 3 1/2 miles. How many times the length of Chase’s bike ride was Maddie’s bike ri

borishaifa [10]

Answer: 2.5 times

Step-by-step explanation:

Given : The length of Chase’s bike ride= $8\dfrac{3}{4}\ miles$

The length of Maddie’s bike ride= $3\dfrac{1}{2}\ miles$

In improper fraction : Length of Chase’s bike ride= $\dfrac{4(8)+3}{4}\ miles$

$=\dfrac{35}{4}\ miles$

Similarly , Length of Maddie’s bike ride= $\dfrac{7}{2}\ miles$

The number of times the length of Chase’s bike ride was Maddie’s bike ride= $\dfrac{\text{ Length of Chase’s bike ride}}{\text{ Length of Maddie’s bike ride}}$

$=\dfrac{\dfrac{35}{4}}{\dfrac{7}{2}}\\\\=\dfrac{5}{2}=2.5$

Hence, the length of Chase’s bike ride was 2.5 times Maddie’s bike ride.

8 0

2 years ago

Please help and first right answer will be marked branliest

lakkis [162]

Answer:

a) 320 students

b) 25 students

Step-by-step explanation:

Number of 18-years old in the survey:

(We add all frequency points for each line)

0 + 30 + 20 + 60 + 70 + 40 + 60 + 40 + 0 = 320 students

Number of 18 year old spending between 25 and 35 minutes: 40 + 65 = 105

Number of 12 year old spending between 25 and 35 minutes: 30 + 50 = 80

105 - 80 = 25 students

5 0

3 years ago

Find the least common multiple (LCM) of 8y^6+ 144y^5+ 640y^4 and 2y^4 + 40y^3 + 200y^2.

Mice21 [21]

Answer:

LCM = $8y^{4}(y+ 10)^{2}(y + 8)$

Step-by-step explanation:

Making factors of $8y^{6}+ 144y^{5}+ 640y^{4}$

Taking $8y^{4}$ common:

$\Rightarrow 8y^{4} (y^{2}+ 18y+ 80)$

Using factorization method:

$\Rightarrow 8y^{4} (y^{2}+ 10y + 8y + 80)\\\Rightarrow 8y^{4} (y (y+ 10) + 8(y + 10))\\\Rightarrow 8y^{4} (y+ 10)(y + 8))\\\Rightarrow \underline{2y^{2}} \times 4y^{2} \underline{(y+ 10)}(y + 8)) ..... (1)$

Now, Making factors of $2y^{4} + 40y^{3} + 200y^{2}$

Taking $2y^{2}$ common:

$\Rightarrow 2y^{2} (y^{2}+ 20y+ 100)$

Using factorization method:

$\Rightarrow 2y^{2} (y^{2}+ 10y+ 10y+ 100)\\\Rightarrow 2y^{2} (y (y+ 10) + 10(y + 10))\\\Rightarrow \underline {2y^{2} (y+ 10)}(y + 10) ............ (2)$

The underlined parts show the Highest Common Factor(HCF).

i.e. HCF is $2y^{2} (y+ 10)$ .

We know the relation between LCM, HCF of the two numbers 'p' , 'q' and the numbers themselves as:

$HCF \times LCM = p \times q$

Using equations (1) and (2): $\Rightarrow 2y^{2} (y+ 10) \times LCM = 2y^{2} \times 4y^{2}(y+ 10)(y + 8) \times 2y^{2} (y+ 10)(y + 10)\\\Rightarrow LCM = 2y^{2} \times 4y^{2}(y+ 10)(y + 8) \times (y + 10)\\\Rightarrow LCM = 8y^{4}(y+ 10)^{2}(y + 8)$

Hence, LCM = $8y^{4}(y+ 10)^{2}(y + 8)$

5 0

2 years ago

(06.04 HC) The graph shows Wilson's science scores versus the number of hours spent doing science homework. A graph titled Wilso

alexandr1967 [171]

Answer:

The answer 55

Step-by-step explanation:

Because it goes up by five for they gave us the amount of point they get for 5 hours and the amount of point he had for 5 hours was 50 so we just needed to add 5 more and 50+5= 55

I don't know if I made myself clear but good luck! :)

5 0

2 years ago