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3 years ago

7

Which is the relationship between photon energy and the color of light?

1 answer:

MatroZZZ [7]3 years ago

3 0

<span>D. Red photons have the least amount of energy.

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I will Give Brainliest To whoever actually answers A 500 kg satellite experiences a gravitational force of 3000 N, while moving

snow_lady [41]

Answer:

$9.7\times 10^{-4}\ rad/s$

Explanation:

Given:

$m=500 kg\\F=3000 N$

$Radius of earth , R=6371 \times 10^3\ m\\Angular speed =\omega\\We\ know\ that\ \\F= m\times \omega^{2} \times R\\\omega^{2}=\frac{F}{m*R} \\\\=\frac{3000}{500*6371 \times 10^3\ m}$

= $\frac{6}{6371 \times 10^3\ m}$

= $9.7\times 10^{-4}\ rad/s$

7 0

3 years ago

A car is moving at a rate of 72 km/hr .How far does car move when it stop after 4 seconds?

Zanzabum

Answer:

Assuming it starts at 72 kmph and hits a dead stop: Divide 72 by 60 for distance per minute. So, 1.2km per minute. 1.2km is 1200m and 4 seconds is one fifteenth of a minute.

Explanation:

5 0

3 years ago

Question 1: Bicycle pump

belka [17]

Answer: The pressure of the air when compressed is $5.0\times 10^5Pa$

Explanation:

Boyle's Law: This law states that pressure is inversely proportional to the volume of the gas at constant temperature and number of moles.

$P\propto \frac{1}{V}$ (At constant temperature and number of moles)

$P_1V_1=P_2V_2$

where,

$P_1$ = initial pressure of gas = $1.0\times 10^5Pa$

$P_2$ = final pressure of gas =?

$V_1$ = initial volume of gas = V

$V_2$ = final volume of gas = $\frac{V}{5}$

$1.0\times 10^5\times V=P_2\times \frac{V}{5}$

$P_2=5.0\times 10^5Pa$

Therefore, the pressure of the air when compressed is $5.0\times 10^5Pa$

4 0

3 years ago

2. Willingness to take turns is one way we can express our attitudes through

leva [86]

B because willingness shows confidence in your answer

3 0

3 years ago

A square coil (length of side = 24 cm) of wire consisting of two turns is placed in a uniform magnetic field that makes an angle

dalvyx [7]

Explanation:

It is given that,

Length of side of a square, l = 24 cm = 0.24 m

The uniform magnetic field makes an angle of 60° with the plane of the coil.

The magnetic field increases by 6.0 mT every 10 ms. We need to find the magnitude of the emf induced in the coil. The induced emf is given by :

$\epsilon=N\dfrac{d\phi}{dt}$

$\dfrac{d\phi}{dt}$ is the rate of change if magnetic flux.

$\phi=BA\ cos\theta$

$\theta$ is the angle between the magnetic field and the normal to area vector.

$\theta=90-60=30$

$\epsilon=NA\dfrac{dB}{dt}\times cos30$

$\epsilon=2\times (0.24\ m)^2\times \dfrac{6\ mT}{10\ mT}\times cos(30)$

$\epsilon=0.0598\ T$

$\epsilon=59.8\ mT$

or

EMF = 60 mT

So, the magnitude of emf induced in the coil is 60 mT. Hence, this is the required solution.

6 0

3 years ago