<span>A. Helium </span>atomic number 2
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<u>Answer:</u> The heat of formation of oleic acid is -94.12 kJ/mol
<u>Explanation:</u>
We are given:
Heat of combustion of oleic acid =
The chemical equation for the combustion of oleic acid follows:
Enthalpy change is defined as the difference in enthalpies of all the product and the reactants each multiplied with their respective number of moles. It is represented as
The equation used to calculate enthalpy change is of a reaction is:
The equation for the enthalpy change of the above reaction is:
We are given:
Putting values in above equation, we get:
Hence, the heat of formation of oleic acid is -94.12 kJ/mol
Answer:
0.536 mol HNO₃
Explanation:
Step 1: Convert 37.0 g of NO₂ into mol NO₂:
37.0 g NO₂ x 1 mol NO₂/46.0 g NO₂ = 0.8043 mol NO₂
Step 2: Convert 0.8043 mol NO₂ into mol HNO₃:
0.8043 mol NO₂ x 2 mol HNO₃/3 mol NO₂ = 0.5362 mol HNO₃
Step 3: Round to 3 significant figures:
0.5362 mol HNO₃ -> 0.536 mol HNO₃
Answer:
legs of table +10N and -10N. fish tank +120.N - 70N. top of table +70N.
+120N. botom of fish tank -120N. and plz dont delit my anser
Explanation:
Molar gas=given volume ÷ molar volume
x=0.5÷22.4=0.02
now=0.02×2.5=0.05
mass =0.05