1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
zepelin [54]
3 years ago
13

spontaneous redox reaction happens between zinc (Zn) and magnesium (Mg) in an electrochemical cell. (6 points) i. Use the reduct

ion potential chart to determine which metal is oxidized and which is reduced. (1 point) ii. Write the half-reactions for this reaction, indicating the oxidation half-reaction and the reduction half-reaction. (1 point) iii. Which metal is the anode, and which is the cathode
Chemistry
1 answer:
aev [14]3 years ago
3 0

<u>Answer:</u>

<u>For (i):</u> Magnesium is getting oxidized and zinc is getting reduced.

<u>For (ii):</u> The half reactions are given below.

<u>For (iii):</u> Magnesium will act as anode and zinc act as cathode.

<u>Explanation:</u>

  • <u>For (i):</u>

E^o_{(Mg^{2+}/Mg)}=-2.37V\\E^o_{(Zn^{2+}/Zn)}=-0.76V

The substance having highest positive E^o potential will always get reduced and will undergo reduction reaction. Here, zinc will always undergo reduction reaction will get reduced.

Magnesium will undergo oxidation reaction and will get oxidized.

  • <u>For (ii):</u>

Oxidation reaction is defined as the reaction in which an atom looses its electrons. The oxidation number of the atom gets increased during this reaction.

X\rightarrow X^{n+}+ne^-

Reduction reaction is defined as the reaction in which an atom gains electrons. The oxidation number of the atom gets reduced during this reaction.

X^{n+}+ne^-\rightarrow X

Oxidation half reaction:  Mg\rightarrow Mg^{2+}+2e^-

Reduction half reaction:  Zn^{2+}+2e^-\rightarrow Zn

  • <u>For (iii):</u>

Oxidation reaction always occurs on anode side and thus, magnesium is acting as anode.

Reduction reaction always occurs on cathode side and thus, zinc is acting as cathode.

You might be interested in
How does the law of conservation of energy apply to the changes in potential and kinetic energy of a pencil as it falls to the f
antiseptic1488 [7]

The changes in the energy law of conservation of energy is Potential energy is converted to kinetic energy. Kinetic energy is converted into potential energy.

<h3>What is the law of conservation of energy?</h3>

Law of conservation of energy says that energy can neither be created nor destroyed, it just transformed from one form to another.

The energies are kinetic, potential, mechanical, gravitational, electrical, etc.

Thus, the changes in the energy law of conservation of energy is Potential energy is converted to kinetic energy. Kinetic energy is converted into potential energy.

Learn more about law of conservation of energy

brainly.com/question/20971995

#SPJ4

7 0
2 years ago
How many moles in 6.57 x 10^24 formula units of NaCl?
laiz [17]

Answer:

3.955*10^48

Explanation:

1 mole of a substance gives 6.02*10^23/6.57*10^24 will give x then cross multiply the answer. is 3.955*10^48

8 0
3 years ago
Solid aluminum (AI) and oxygen (O_2) gas react to form solid aluminum oxide (Al_2O_3). Suppose you have 7.0 mol of Al and 9.0 mo
Nimfa-mama [501]

Answer:

There will be formed 3.5 moles of Al2O3 ( 356.9 grams)

Explanation:

Step 1: Data given

Numbers of Al = 7.0 mol

Numbers of mol O2 = O2

Molar mass of Al = 26.98 g/mol

Molar mass of O2 = 32 g/mol

Step 2: The balanced equation

4Al(s) + 3O2(g) → 2Al2O3(s)  

Step 3: Calculate limiting reactant

For 4 moles Al we need 3 moles O2 to produce 2 moles Al2O3

Al is the limiting reactant, it will be consumed completely (7 moles).

O2 is in excess.  There will react 3/4 * 7 = 5.25 moles

There will remain 9-5.25 = 3.75 moles

Step 4: Calculate moles Al2O3

For 4 moles Al we'll have 2moles Al2O3

For 7.0 moles of Al we'll have 3.5 moles of Al2O3 produced

Step 5: Calculate mass of Al2O3

Mass Al2O3 = moles Al2O3 * molar mass Al2O3

Mass Al2O3 = 3.5 moles* 101.96 g/mol

Mass Al2O3 = 356.9 grams

There will be formed 3.5 moles of Al2O3 ( 356.9 grams)

3 0
3 years ago
Identify the Brønsted-Lowry acid, the Brønsted-Lowry base, the conjugate acid, and the conjugate base in each reaction:
ExtremeBDS [4]

Answer:

C5H5N is the base and C5H5NH+ is the conjugate acid

H2O is the acid and OH− is the conjugate base

Explanation:

<u>Hydrogen + is also called a proton</u>

C5H5N is the base because it receives the proton (H+) and C5H5NH+ is its conjugate acid

H2O is the acid  because it gives up the proton and OH− is the conjugate base because it is capable of receiving the proton

Answer:

HNO3 is the acid and NO3- is the conjugate base

H2O is the base and H3O+ is the conjugate acid

Explanation

HNO3 is the acid and NO3− is its conjugate base, capable of receiving a proton

H2O is the base because it receives the proton and H3O+ is a conjugate acid capable of giving up the proton.

3 0
3 years ago
Chlorophyll pigments are separated using paper. what is the stationary phase in this experiment
Llana [10]
Paper is a stationary phase
4 0
3 years ago
Other questions:
  • An ionic solid is placed in water. which information is described by the solubility product constant?
    9·2 answers
  • What is the molecular weight of one mole of H2O?
    8·1 answer
  • Explain the environmental benefits of recyling paper products.
    12·1 answer
  • Carbon-14 has a half-life of 5,730 years. In how many years will 120 grams of Carbon-14 decay to 15 grams? 11,460 years 17,190 y
    14·1 answer
  • Please help fast!!
    12·2 answers
  • How many grams is .15mol of argon
    6·1 answer
  • ____ KClO3-----&gt; ____ KCl + ____O3
    9·2 answers
  • gastric juice (ph 1.5) is produced by pumping HCl from blood plasma (ph 7.4) into the stomach. Calculate the amount of free ener
    11·1 answer
  • 0.385g of 17Cl is how many atoms?
    7·1 answer
  • What is the difference between physics and chemistry laboratory (4)
    15·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!