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DIA [1.3K]
3 years ago
12

What is the percent by mass of carbon in C10 H14 N2?

Chemistry
2 answers:
MrMuchimi3 years ago
8 0
Multiply the number of each element by its mass on the periodic table.

Add them together.

Put the mass of carbon only over the total mass and multiply the result by 100 to get the percentage.
Talja [164]3 years ago
7 0

<u>Answer:</u> The percentage by mass of carbon in the given compound is 45.8 %

<u>Explanation:</u>

We are given a chemical compound having chemical formula C_{10}H_{14}N_2

To calculate the percentage composition of an element in a compound, we use the equation:

\%\text{ composition}=\frac{\text{Mass of carbon element}}{\text{Mass of compound}}\times 100

In 1 mole of given compound, 10 moles of carbon atoms are there.  

Mass of C_{10}H_{14}N_2= [(10\times 12)+(14 \times 1)+(2\times 14)]=262g/mol

Mass of carbon element = [10\times 12]=120g/mol

Putting values in above equation, we get:

\%\text{ composition of carbon}=\frac{120}{262}\times 100=45.8\%

Hence, percentage of carbon in given compound is 45.8 %.

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Look up the active ingredient in baking soda. Write a molecular and net ionic equation when that active ingredient is mixed with
Volgvan

Answer:

The active ingredients in baking soda (NaHCO3) are

Na^+ and HCO3^-

when Baking soda reacts with Acetic acid

Molecular equation

 NaHCO3(aq) + CH3COOH(aq) → Na(CH3COO)(aq) + CO2(g) +H2O(l)

Ionic equation

Na^+ + HCO3^-  + CH3COOH →   Na^+ + CH3COO^-  +CO2 + H2O

as Na^+ is present on both sides so it will cancel out and the net ionic equation will be

HCO3^-(aq) + CH3COOH(aq) → CH3COO^-(aq) + CO2(g) + H2O(l)

6 0
3 years ago
How does an elements period number related to the number of the energy level of its valence electrons?
Mrac [35]
<span>There is a direct correlation between the period number and the energy level for valence electrons. For example, the H and He elements, in period 1, have their outer electrons in the energy level "1". This continues down the rows: all the elements in period 2 have their principal energy level as n = 2, period 3 has n = 3, and so on.</span>
3 0
4 years ago
Describe the physical and chemical weathering​
Stella [2.4K]

Answer:

Physical weathering is caused by purely mechanical changes to the rock, while chemical weathering is caused by chemical reactions.

Explanation:

Chemical weathering happens when the chemicals get diluted and dissolved in water and seep and percolate down the rock surfaces.

Physical weathering happens when rocks are fragmented into minor fragments while ensuring no alterations in their chemical makeup. The main causes behind physical weathering include spontaneous fluctuations in temperature like too high or too low heat or cold

7 0
3 years ago
Read 2 more answers
Consider the reaction CH4(g) 2O2(g)CO2(g) 2H2O(g) Using standard thermodynamic data at 298K, calculate the entropy change for th
zvonat [6]

Answer:

the entropy change for the surroundings when 1.62 moles of CH4(g) react at standard conditions is −8.343 J/K

Explanation:

The balanced chemical equation of the reaction in the question given is:

CH_{4(g)}  + 2O_{2(g)} \to CO_{2(g)} + 2 H_2O _{(g)}

Using standard thermodynamic data at 298K.

The entropy of each compound above are listed as follows in a respective order.

Entropy of (CH4(g)) = 186.264 J/mol.K

Entropy of (O2(g)) = 205.138 J/mol.K

Entropy of (CO2(g)) = 213.74 J/mol.K

Entropy of (H2O(g)) = 188.825 J/mol.K

The change in Entropy (S) of the reaction is therefore calculated as follows:

=1*S(CO2(g)) + 2*S(H2O(g)) - 1*S( CH4(g)) - 2*S(O2(g))

=1*(213.74) + 2*(188.825) - 1*(186.264) - 2*(205.138)

=  -5.15  J/mol.K

Given that :

the number of moles = 1.62 of CH4(g) react at standard conditions.

Then;

The change in entropy of the rxn = 1.62 \ mol * -5.15 \  J/mol.K

= −8.343 J/K

6 0
3 years ago
I do not understand this question
boyakko [2]

Answer:

the answer should be c

Explanation: why because 37/19 k toward 0+1e +37/18 AR is equivalent to the beta decay and it describes the best beta decay in the formula.

6 0
3 years ago
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