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3 years ago

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What is the percent by mass of carbon in C10 H14 N2?

2 answers:

MrMuchimi3 years ago

8 0

Multiply the number of each element by its mass on the periodic table.

Add them together.

Put the mass of carbon only over the total mass and multiply the result by 100 to get the percentage.

Talja [164]3 years ago

7 0

<u>Answer:</u> The percentage by mass of carbon in the given compound is 45.8 %

<u>Explanation:</u>

We are given a chemical compound having chemical formula $C_{10}H_{14}N_2$

To calculate the percentage composition of an element in a compound, we use the equation:

$\%\text{ composition}=\frac{\text{Mass of carbon element}}{\text{Mass of compound}}\times 100$

In 1 mole of given compound, 10 moles of carbon atoms are there.

Mass of $C_{10}H_{14}N_2= [(10\times 12)+(14 \times 1)+(2\times 14)]=262g/mol$

Mass of carbon element = $[10\times 12]=120g/mol$

Putting values in above equation, we get:

$\%\text{ composition of carbon}=\frac{120}{262}\times 100=45.8\%$

Hence, percentage of carbon in given compound is 45.8 %.

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Carbon dioxide dissolves in water to form carbonic acid, which is primarily dissolved CO2. Dissolved CO2 satisfies the equilibri

lorasvet [3.4K]

Explanation:

The reaction equation will be as follows.

$CO_{2}(aq) + H_{2}O \rightleftharpoons H^{+}(aq) + HCO^{-}_{3}(aq)$

Calculate the amount of $CO_{2}$ dissolved as follows.

$CO_{2}(aq) = K_{CO_{2}} \times P_{CO_{2}}$

It is given that $K_{CO_{2}}$ = 0.032 M/atm and $P_{CO_{2}}$ = $1.9 \times 10^{-4}$ atm.

Hence, $[CO_{2}]$ will be calculated as follows.

$[CO_{2}]$ = $K_{CO_{2}} \times P_{CO_{2}}$

= $0.032 M/atm \times 1.9 \times 10^{-4}atm$

= $0.0608 \times 10^{-4}$

or, = $0.608 \times 10^{-5}$

It is given that $K_{a} = 4.46 \times 10^{-7}$

As, $K_{a} = \frac{[H^{+}]^{2}}{[CO_{2}]}$

$4.46 \times 10^{-7} = \frac{[H^{+}]^{2}}{0.608 \times 10^{-5}}$

$[H^{+}]^{2}$ = $2.71 \times 10^{-12}$

$[H^{+}]$ = $1.64 \times 10^{-6}$

Since, we know that pH = $-log [H^{+}]$

So, pH = $-log (1.64 \times 10^{-6})$

= 5.7

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ziro4ka [17]

Answer:

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What is the identity of a 100. g sample of metal that, upon absorbing 4680 J of heat, increases in temperature by 52.0°C?

krok68 [10]

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<u>Explanation:</u>

Given:

Heat, q = 4680 J

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sample = ?

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