All categories

3 years ago

What is the volume of 5.00 mole of an unknown gas at STP

Chemistry

1 answer:

ivann1987 [24]3 years ago

5 0

Answer:

What is the volume of gas at 2.00 atm and 200.0 K if its original volume was. 200.0 L at STP How many moles of nitrogen gas will occupy a volume of 150 L at STP? n=pr 11.00atm) What is the mass of 5.00 L of NO2 gas at STP? PV = nRT.

Explanation:

You might be interested in

You determine that it takes 26.0 mL of base to neutralize a sample of your unknown acid solution. The pH of the solution was 7.8

Lubov Fominskaja [6]

Complete Question

You determine that it takes 26.0 mL of base to neutralize a sample of your unknown acid solution. The pH of the solution was 7.82 when exactly 13 mL of base had been added, you notice that the concentration of the unknown acid was 0.1 M. What is the pKa of your unknown acid?

Answer:

The pK_a value is $pK_a =7.82$

Explanation:

From the question we are told

The volume of base is $V_B = 26.mL = 0.0260L$

The pH of solution is $pH = 7.82$

The concentration of the acid is $C_A = 0.1M$

From the pH we can see that the titration is between a strong base and a weak acid

Let assume that the the volume of acid is $V_A = 18mL= 0.018L$

Generally the concentration of base

$C_B = \frac{C_AV_A}{C_B}$

Substituting value

$C_B = \frac{0.1 * 0.01800}{0.0260}$

$C_B= 0.0692M$

When 13mL of the base is added a buffer is formed

The chemical equation of the reaction is

$HA_{(aq)} + OH^-_{(aq)} --------> A^{+}_{(aq)} + H_2 O_{(l)}$

Now before the reaction the number of mole of base is

$No \ of \ moles[N_B] = C_B * V_B$

Substituting value

$N_B = 0.01300 * 0.0692$

$= 0.0009 \ moles$

Now before the reaction the number of mole of acid is

$No \ of \ moles = C_B * V_B$

Substituting value

$N_A = 0.01800 *0.1$

$= 0.001800 \ moles$

Now after the reaction the number of moles of base is zero i.e has been used up

this mathematically represented as

$N_B ' = N_B - N_B = 0$

The number of moles of acid is

$N_A ' = N_A - N_B$

$= 0.0009\ moles$

The pH of this reaction can be mathematically represented as

$pH = pK_a + log \frac{[base]}{[acid]}$

Substituting values

$7.82 = pK_a +log \frac{0.0009}{0.0009}$

$pK_a =7.82$

8 0

3 years ago

Give two different conditions under which long chain hydrocarbons may be cracked.

sammy [17]

In thermal cracking, high temperatures (typically in the range of 450°C to 750°C) and pressures (up to about 70 atmospheres) are used to break the large hydrocarbons into smaller ones. Thermal cracking gives mixtures of products containing high proportions of hydrocarbons with double bonds - alkenes.

5 0

3 years ago

What is the overall equation for the covalent bond in H2O . Is it H2 + O2=H2O OR. H2 + O = H2O

AlexFokin [52]

Answer:

The answer is in the photo

Explanation:

I hope that is useful for you :)

4 0

3 years ago

Calculate: A. Mercury has a specific Heat Capacity of 0.14 J/goC. How much heat is needed to raise the thermometer temperature 1

kari74 [83]

Answer:

$\boxed {\boxed {\sf 56 \ Joules}}$

Explanation:

We are given the mass, specific heat, and temperature, so we must use this formula for heat energy.

$q=mc \Delta T$

The mass is 5 grams, the specific heat capacity is 0.14 Joules per gram degree Celsius. Let's find the change in temperature.

ΔT= final temperature - initial temperature
ΔT= 95°C - 15°C = 80°C

We know the variables and can substitute them into the formula.

$m= 5 \ g \\c= 0.14 \ J/ g \ \textdegree C \\\Delta T= 80 \ \textdegree C$

$q= (5 \ g )( 0.14 \ J/ g \ \textdegree C ) ( 80 \ \textdegree C)$

Multiply the first numbers. The grams will cancel.

$q= 0.7 \ J/ \textdegree C(80 \ \textdegree C )$

Multiply again. This time the degrees Celsius cancel.

$q= 56 \ J$

56 Joules of heat are needed.

4 0

3 years ago

When liquid gold becomes a solid, its particles get closer together. Which best describes what happened to the gold?

yanalaym [24]

Answer:

The rearrangement of particles in a physical change.

Explanation:

When things are liquid the particles tend to be spread out because they aren't tightly compacted as they would be with a solid. So when liquid gold is changing from a liquid to a solid the properties are changing and the particles in the gold are getting closer together.

7 0

3 years ago

Read 2 more answers