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uranmaximum [27]
3 years ago
8

A ball with a mass of 4 kg is initially traveling at 2 m/s and has a 5 N force applied for 3 s. What is the initial momentum of

the ball?
Physics
1 answer:
RUDIKE [14]3 years ago
7 0

Answer:

The initial momentum of the ball is 8 kg-m/s.

Explanation:

Given that,

Mass of the ball is 4 kg

Initial speed of the ball is 2 m/s

Force applied to the ball is 5 N for 3 seconds

It is required to find the initial momentum of the ball. Initial momentum means that the product of mass and initial velocity of the ball. It is given as :

p_i=mu\\\\p_i=4\ kg\times 2\ m/s\\\\p_i=8\ kg-m/s

So, the initial momentum of the ball is 8 kg-m/s.

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The (Close) of matter depends upon how close the individual particles are together
4 0
4 years ago
An ice cube of volume 15 cm^3 and density 917 kg/m^3 is placed in ethyl alcohol of density 811 kg/m^3. What is the buoyant force
Amiraneli [1.4K]

Answer:

the buoyant force acting on the  ice cube is 0.119 N

Explanation:

given,

volume of ice cube = 15 cm³ = 15 × 10⁻⁶ m³

density of ice cube = 917 kg/m³

density of ethyl alcohol = 811 kg/m³

buoyant force = ?

The density of ice is more than ethyl alcohol hence it will sink.

buoyant  force acting on the ice cube = ρ V g

                                                                = 811 × 15 × 10⁻⁶ × 9.81

                                                                =0.119 N

so, the buoyant force acting on the  ice cube is 0.119 N

3 0
3 years ago
a sailboat sails 50 km to the north then 80 km in the direction 38 degrees west of south. what is the net displacement of the bo
True [87]

Answer:

35.489km

Explanation:

a diagram illustrating the question is attached

now, applying cosine rule to find the displacement c

cosine rule;

c²=a²+b²-2abCos ∅

c²=50²+80²-2(50)(80)Cos 38°

c²=2500 + 6400 - (8000×0.9951)

c²=8900-7640.589

c²=1259.411

c=\sqrt{1259.411}

c=35.49km

8 0
4 years ago
Read 2 more answers
Do only number 3 and thank
IrinaK [193]

Charge = 0.2 Ah is the correct answer...

3 0
3 years ago
7. A 3.0 kg object travels vertically at a constant
vladimir2022 [97]

Answer:

220.7

Explanation:

distance traveled is 1.5*5=7.5m

PE gain is MGH=3*9.81*7.5=220.7

7 0
3 years ago
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