Answer:
500km
Explanation:
Given parameters:
Speed = 200km/hr
Time taken = 2.5hrs
Unknown:
Distance = ?
Solution:
To solve this problem, we use the speed, time and distance equation.
Therefore;
Distance = Speed x time
So;
Distance = 200 x 2.5 = 500km
Answer:
Tension in the string is equal to 58.33 N ( this will be the strength of the string )
Explanation:
We have given mass m = 1.7 kg
radius of the circle r = 0.48 m
Kinetic energy is given 14 J
Kinetic energy is equal to 
So 

v = 4.05 m/sec
Centripetal force is equal to 
So tension in the string will be equal to 58.33 N ( this will be the strength of the string )
Answer:
The Physical Behavior of Objects when Gravity is Missing
In order to be able to form a concept of the general physical conditions existing in a weightless state, the following must be noted: the force of the Earth's gravity pulling all masses down to the ground and thus ordering them according to a certain regularity is no longer active.
Answer:
right is the correct answer to the given question .
Explanation:
In this question figure is missing
The main objective right-hand rule to decide the position of the magnetic force on the positive force acting, either the position of the thumb of a right hand with in position of v, the fingers throughout the position of B1, and a right angles throughout the position of F1 to the hand positions.
So 
- So from the magnetic right hand rule the direction of the magnetic field in front of a wire is right .
- All the others options are incorrect because they do not give the direction of the magnetic field in front of a wire is right .
<span>Answer:
Well, let's start by finding the pressure due to the "extra" height of the mercury.
p = 1.36e4 kg/m³ · (0.105m - 0.05m) · 9.8m/s² = 7330 N/m² = 7330 Pa
The pressure at B is clearly p_b = p_atmos = p_gas + 7330 Pa
The pressure at A is p_a = p_gas = p_atmos - 7330 Pa
c) 1 atm = 101 325 Pa
Then p_gas = 101325 Pa - 7330 Pa = 93 995 Pa</span>