Depends on where the object is. On earth, moon , or somewhere without any other mass (theoretically). I think you mean how much does weigh on earth. So, the average gravitational acceleration on earth is : 9.83 m/s^2 To find out how much an object weighs, this is the formula : G=m.g where m is mass of the object g is the gravitational acceleration and G is weight. So, G = 10.9,83 = 98,3 N is the answer.
Answer:
decrease
Explanation:
Atomic radius
:
It is the distance from the center of nucleus to the outer most electronic shell.
Trend along period:
As we move from left to right across the periodic table the number of valance electrons in an atom increase. The atomic size tend to decrease in same period of periodic table because the electrons are added with in the same shell. When the electron are added, at the same time protons are also added in the nucleus. The positive charge is going to increase and this charge is greater in effect than the charge of electrons. This effect lead to the greater nuclear attraction. The electrons are pull towards the nucleus and valance shell get closer to the nucleus. As a result of this greater nuclear attraction atomic radius decreases and ionization energy increases because it is very difficult to remove the electron from atom and more energy is required
Answer:
Protons: 84
Neutrons: 127
Explanation:
The number of protons is the atomic number. The number of neutrons can be found by subtracting the proton number (84) from the isotope number (211)
acid
when a metal hydroxide reacts with acid it forms a salt and water, for example:
lithium hydroxide + hydrochloric acid → lithium chloride (the salt) + water
Answer:
a. The new pressure is 606,25 Torr.
b. -243,9°C is needed to reach the pressure of 7250 Torr.
Explanation:
Gay Lussac's law for gases says that if the volume in a gas remains constant, the pressure will be directly proportional to the temperature change.
P1 . T1 = P2. T2
(Temperature must be in K)
725 Torr . 291 K = P2 . 348 K
(725 Torr . 291 K) /348 K = P2
606,25 Torr = P2
725 Torr . 291K = 7250 Torr . T2
(725 Torr . 291K) /7250 Torr = T2
29,1 K = T2
T° K - 273 = T°C
29,1 K -273 = -243,9°C
