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andreyandreev [35.5K]
3 years ago
8

Pls answer ASAP will mark brainiest

Physics
1 answer:
professor190 [17]3 years ago
3 0
First one is a
I’ll answer one by one
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A hand pump is being used to inflate a bicycle tire that has a gauge pressure of 59.0 lb/in2. If the pump is a cylinder of lengt
bagirrra123 [75]

Answer:

∴The air cannot be made to flow in with the given pump at the given conditions.

Explanation:

Given:

  • gauge pressure of bicycle tyre, P_g=59\ lb.in^{-2}
  • length of cylinder of the pump, l=17.4\ in
  • area of the the cylinder of the pump, a= 3\ in^2
  • we have the density of air at STP, \rho=4.4256\times 10^{-5}\ lb.in^{-2}

The piston must be pushed more than the pressure inside the tyre:

P_g=\rho\times V\div a

59=4.4256\times 10^{-5}\times a\times h\div a

h=13.33\times 10^5\ in

∴The air cannot be made to flow in with the given pump at the given conditions.

4 0
3 years ago
A uniformly charged ring of radius 10.0 cm has a total charge of 50.0 μC Find the electric field on the axis of the ring at 30.0
Grace [21]

Answer: 4.27 *10^6 N/C

Explanation: In order to calculate the electric field along the axis of charged ring we have to use the following expression:

E=k*x/(a^2+x^2)^3/2    where a is the ring radius and x the distance to the point measured from the center of the ring.

Replacing the data we have:

E= (9* 10^9* 0.3* 50 * 10^-6)/(0.1^2+0.3^2)^3/2

then

E=4.27 * 10^6 N/C

8 0
3 years ago
What must be true of a force that causes an object to move in a circular motion?
AlladinOne [14]

Before going to answer this question, first we have to understand centripetal force.

The centripetal force is the force which is required to keep the body along its circular path.The direction of the force is along the radius and towards the centre.

Mathematically\ centripetal\ force\ F_{c} =\frac{mv^2}{r}

Here m is the mass of the body,v is the velocity of the body and r is the radius of the circular path.

When a body moves in a circular path,its velocity at any point is the tangent drawn at that point.

As centripetal force acts along the radius, it must be perpendicular to the velocity of the body.

Hence the correct answer to the question is- It acts perpendicular to the velocity and is directed toward the center of the circle.


7 0
3 years ago
Read 2 more answers
On the surface of the earth, weight is calculated by:
sdas [7]

On the surface of the earth, weight is calculated by multiplying mass and gravity.

 

<span>Because we know the radius of the Earth, we can use the Law of Universal Gravitation to calculate the mass of the Earth in terms of the gravitational force on an object (its weight) at the Earth's surface, using the radius of the Earth as the distance. We also need the Constant of Proportionality in the Law of Universal Gravitation, G. This value was experimentally determined by Henry Cavendish in the 18th century to be the extemely small force of 6.67 x 10</span>-11 Newtons between two objects weighing one kilogram each and separated by one meter. Cavendish determined this constant by accurately measuring the horizontal force between metal spheres in an experiment sometimes referred to as "weighing the earth."

 

 

The correct answer between all the choices given is the third choice or letter C. I am hoping that this answer has satisfied your query and it will be able to help you in your endeavor, and if you would like, feel free to ask another question.

8 0
4 years ago
Read 2 more answers
PLEASE HELP THIS IS TIMED
Harlamova29_29 [7]

Answer:

85 N backwards

Explanation:

u subtract then thats the net force and add direction

8 0
3 years ago
Read 2 more answers
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