4 years ago

How many atoms of Al(OH)3 in a 72 gram sample? please show work

Chemistry

1 answer:

Lostsunrise [7]4 years ago

4 0

Answer:

5.559*10^(23) atoms

Explanation:

Molar Mass of Al(OH)3 = 78 g/mol

(72g/78g/mol)*(6.022*10^(23)atoms/mol) = 5.559*10^(23) atoms in 72 grams of Al(OH)3

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How many atoms of Al(OH)3 in a 72 gram sample? please show work​

How many atoms of Al(OH)3 in a 72 gram sample? please show work