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Veronika [31]
3 years ago
7

The medium seismic waves travel through is

Physics
2 answers:
Natalija [7]3 years ago
5 0

Answer:

rocks and other materials inside the Earth. 5.

Explanation:

Lunna [17]3 years ago
3 0

Answer:

The medium seismic waves travel through is rocks and other materials inside the Earth.

Explanation:

Seismic waves travel through all sorts of things, earthquakes mainly affect the ground, so smaller waves usually travel through the ground.

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A bobsled team accelerates the sled to go to 150 m/s in 3 seconds from rest.(a)What is the
Sergeeva-Olga [200]

Answer:

Explanation:

From the equation of Newton's laws of motion

v = u + at where v is final velocity , u is initial velocity and t is time.

150 = 0 + a x 3

a = 50 m / s ²

s = ut + 1/2 at²  ; s is distance travelled

s = 50 x 3 + .5 x 50 x 3²

= 150 + 225

= 375 m .

7 0
3 years ago
What is the distance moved by a horse galloping at 75 km/h in 10.0 s?
skelet666 [1.2K]

125Answer:

Explanation:uruhavdfh

4 0
3 years ago
43 kg bear slides, from rest, 15 m down a lodgepole pine tree, moving with a speed of 5.5 m/s just before hitting the ground. (a
olga2289 [7]

Answer:

-6327.45 Joules

650.375 Joules

378.47166 N

Explanation:

h = Height the bear slides from = 15 m

m = Mass of bear = 43 kg

g = Acceleration due to gravity = 9.81 m/s²

v = Velocity of bear = 5.5 m/s

f = Frictional force

Potential energy is given by

P=mgh\\\Rightarrow P=43\times -9.81\times 15\\\Rightarrow P=-6327.45\ J

Change that occurs in the gravitational potential energy of the bear-Earth system during the slide is -6327.45 Joules

Kinetic energy is given by

K=\frac{1}{2}mv^2\\\Rightarrow K=\frac{1}{2}\times 43\times 5.5^2\\\Rightarrow K=650.375\ J

Kinetic energy of the bear just before hitting the ground is 650.375 Joules

Change in total energy is given by

\Delta E=fh=-(\Delta K+\Delta P)\\\Rightarrow fh=-(650.375-6327.45)\\\Rightarrow fh=5677.075\\\Rightarrow f=\frac{5677.075}{h}\\\Rightarrow f=\frac{5677.075}{15}\\\Rightarrow f=378.47166\ N

The frictional force that acts on the sliding bear is 378.47166 N

5 0
3 years ago
Read 2 more answers
A 10.0 Ω lightbulb is connected to a 12.0 V battery. (a) What current flows through the bulb? (b) What is the power of the bulb?
andreev551 [17]

The current flowing through the bulb as well the power of the bulb are 1.2A and 14.4 Watts respectively.

<h3>What current flows through the bulb as well as the power of the bulb?</h3>

From ohm's law; V = I × R

Where V is the voltage, I is the current and R is the resistance.

Also, Power is expressed as; P = V × I

Where V is voltage and I is current.

Given that;

  • Resistance R = 10.0 ohms
  • Voltage V = 12.0V
  • Current I = ?
  • Power P = ?

First, we determine the current flow through the bulb.

V = I × R

12.0V = I × 10.0 ohms

I = 12.0 ÷ 10.0

I = 1.2A

Next, we determine the power of the bulb.

P = V × I

P = 12.0V × 1.2A

P = 14.4 Watts

Therefore, the current flowing through the bulb as well the power of the bulb are 1.2A and 14.4 Watts respectively.

Learn more about Ohm's law here: brainly.com/question/12948166

#SPJ1

6 0
1 year ago
If it takes 32,000 joules of heat to warm 750 g of water, what was the temperature change?(the specific heat of water is 4.18 J/
Firdavs [7]

Answer:

10.21°C

Explanation:

From the question,we are given;

  • Quantity of heat = 32,000 Joules
  • Mass of water = 750 g
  • Specific heat capacity of water = 4.18 J/g°C

We are required to calculate the change in temperature;

  • We need to know that quantity of heat is calculated by multiplying mass by specific heat then by change in temperature.
  • That is;

Q = m × c × ΔT

Rearranging the formula;

ΔT = (Q ÷ (m × c))

     = 32,000 J ÷ (750× 4.18 J/g°C)

     = 10.21°C

Therefore, the change in temperature  is 10.21°C

7 0
3 years ago
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