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andrew11 [14]
3 years ago
13

If it takes 32,000 joules of heat to warm 750 g of water, what was the temperature change?(the specific heat of water is 4.18 J/

goC)
Thank you!
Physics
1 answer:
Firdavs [7]3 years ago
7 0

Answer:

10.21°C

Explanation:

From the question,we are given;

  • Quantity of heat = 32,000 Joules
  • Mass of water = 750 g
  • Specific heat capacity of water = 4.18 J/g°C

We are required to calculate the change in temperature;

  • We need to know that quantity of heat is calculated by multiplying mass by specific heat then by change in temperature.
  • That is;

Q = m × c × ΔT

Rearranging the formula;

ΔT = (Q ÷ (m × c))

     = 32,000 J ÷ (750× 4.18 J/g°C)

     = 10.21°C

Therefore, the change in temperature  is 10.21°C

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