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andrew11 [14]
3 years ago
13

If it takes 32,000 joules of heat to warm 750 g of water, what was the temperature change?(the specific heat of water is 4.18 J/

goC)
Thank you!
Physics
1 answer:
Firdavs [7]3 years ago
7 0

Answer:

10.21°C

Explanation:

From the question,we are given;

  • Quantity of heat = 32,000 Joules
  • Mass of water = 750 g
  • Specific heat capacity of water = 4.18 J/g°C

We are required to calculate the change in temperature;

  • We need to know that quantity of heat is calculated by multiplying mass by specific heat then by change in temperature.
  • That is;

Q = m × c × ΔT

Rearranging the formula;

ΔT = (Q ÷ (m × c))

     = 32,000 J ÷ (750× 4.18 J/g°C)

     = 10.21°C

Therefore, the change in temperature  is 10.21°C

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Answer:

1. False

2. True

3. True

Explanation:

1- False —> The relation between electric potential and electric field is given such that

-\int\limits^a_b \vec{E}d\vec{l} = V_{ab}

Therefore, for a uniform E field, electric potential is linearly proportional to the distance.

2- True —> The electric field lines always cross the equipotential lines perpendicularly.

3- True —> In order to be a potential difference, one source of electric field is enough. The electric potential will decrease radially according to the following formula:

V = \frac{1}{4\pi\epsilon_0}\frac{q}{r^2}

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3 years ago
A uniform thin rod of mass ????=3.41 kg pivots about an axis through its center and perpendicular to its length. Two small bodie
vivado [14]

Answer:

The length of the rod for the condition on the question to be met is L  =  1.5077 \ m

Explanation:

The  Diagram for this  question is  gotten from the first uploaded image  

From the question we are told that

          The mass of the rod is M  =  3.41 \ kg

           The mass of each small bodies is  m =  0.249 \ kg

           The moment of inertia of the three-body system with respect to the described axis is   I  =  0.929 \ kg \cdot  m^2

             The length of the rod is  L  

     Generally the moment of inertia of this three-body system with respect to the described axis can be mathematically represented as

        I =  I_r + 2 I_m

Where  I_r is the moment of inertia of the rod about the describe axis which is mathematically represented as  

        I_r  =  \frac{ML^2 }{12}

And   I_m the  moment of inertia of the two small bodies which (from the diagram can be assumed as two small spheres) can be mathematically represented  as

           I_m  =   m * [\frac{L} {2} ]^2 =  m*  \frac{L^2}{4}

Thus  2 *  I_m  =  2 *  m  \frac{L^2}{4}  = m  *  \frac{L^2}{2}

Hence

       I  =  M  *   \frac{L^2}{12}  +  m  * \frac{L^2}{2}

=>   I  =    [\frac{M}{12}  + \frac{m}{2}] L^2

substituting vales  we have  

        0.929   =    [\frac{3.41}{12}  + \frac{0.249}{2}] L^2

       L  =  \sqrt{\frac{0.929}{0.40867} }

      L  =  1.5077 \ m

     

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Answer:

Only the perpendicular component of gravity is responsible for the rotation because wind points toward the pivot.

Explanation:

A pinwheel is a plaything that is made up of paper that is designed to spin when the wind comes in contact with it. The paper is held fast to its axle by a pin which enables it to spin.

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