Answer:
Fe + 3CuNO₃ → Fe(NO₃)₃ + 3Cu
Explanation:
- Copper (I) nitrate = CuNO₃ (Nitrate, NO₃⁻, always has a charge of -1).
- Iron (III) nitrate = Fe(NO₃)₃ (That way the compound has an overall neutral charge)
Writing the equation using symbols leaves us with:
- Fe + CuNO₃ → Fe(NO₃)₃ + Cu
<em>It is not balanced yet</em>. Now we <u>balance the NO₃ species on the left side</u>:
- Fe + 3CuNO₃ → Fe(NO₃)₃ + Cu
Finally we<u> balance the Cu species on the right side</u>:
- Fe + 3CuNO₃ → Fe(NO₃)₃ + 3Cu
Answer:
0.0253 M/s
Explanation:
From the reaction
N₂ + 3H₂ → 2NH₃
The rate of reaction can be written as
Rate = -
= -
= + ![\frac{1}{2} \frac{d[NH_3]}{dt}](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B2%7D%20%5Cfrac%7Bd%5BNH_3%5D%7D%7Bdt%7D)
From the above rate equation we can conclude that the rate of reaction of N₂ is equal to one third of the rate of reaction of H₂,
So,
Rate of reaction of molecular nitrogen = 
Upon calculation, we get rate of reaction of molecular nitrogen = 0.0253 M/s
Answer:
the volume is 12.79ml
Explanation:
12.8+12.7+12.78+12.88=51.16
51.16/4
=12.79
It’s a or b i think it’s b