Answer:
1.48 Mpa
Explanation:
Given that For a polymer that was maintained at constant strain, an initial stress of 2.76 MPa decreases to 1.72 MPa after 6 hr. To estimate the stress remaining after 30 hr, we must first find the decay constant by using the exponential equation.
Therefore, the estimate of the stress remaining after 30 hr, is 1.48Mpa.
Please find the attached file for the solution.
Answer:
Explanation:
We shall apply law of conservation of momentum .
m₁ v₁ = m₂ v₂
m₁ = 80 kg
v₁ = ?
m₂ = .43 kg
v₂ = 15 m /s
80 v₁ = .43 x 15
v₁ = .43 x 15 / 80
= .08 m /s
8 cm /s
option A is correct.
Law of conservation of momentum is applied only where no external force acts . Here during the period when ball was thrown , apart from internal force , external force like gravitational force was also acting but we still applied this law because the time duration of action of throw was very small
so we neglected the effect of external force . So it was just an approximation.
Answer:
m = 1.45 kg
Explanation:
For this exercise we look for size reduction in height
Reduction = y / y₀
Reduction = 2.15 / 6.75
Reduction = 0.3185
As the statue should not be deformed, all reduction has the same factor.
Let's use the concept of density
ρ = m / V
Initial statue
ρ = m₀ / V₀
It is reduced
V = x y z
V = 0.3185 x₀ 0.3185 y₀ 0.3185 z₀
V = 0.3185³ V₀
Density is
ρ = m / V
ρ = m / 0.3185³ V₀
As the density remains constant we can match them
m₀ / Vo = m / 0.3185³ V₀
m = 0.3185³ m₀
Let's calculate
m = 0.3185³ 45
m = 0.03231 45
m = 1.45 kg
G is the answer for apex vs / Chehhhh
