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serious [3.7K]
4 years ago
14

1.

Physics
2 answers:
xz_007 [3.2K]4 years ago
5 0

Answer: A. All of the answers are correct.

Anton [14]4 years ago
5 0

Answer:

A. All are correct

Explanation:

When a force is applied on an object, that object is accelerated. Acceleration is a change in the objects speed

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A car is traveling at a constant speed on the highway. Its tires have a diameter of 65.0 cm and are rolling without sliding or s
lesya692 [45]

Answer:

Explanation:

The car is rolling without slipping so Vcm= R×ω = 0.325×49 = 16

4 0
3 years ago
Using planck's constant and a wavelength of 656e-9 what is the energy of the photon
lbvjy [14]

Answer:

3.03e-19 J

Explanation:

Use the formula E = hc/λ

Where:

h (Planck's constant) = 6.626e-34 J*s

c (speed of light, constant) = 3.00e8 m/s

λ (wavelength) = 656e-9 m

E = energy (in Joules)

E = (6.626e-34 * 3.00e8) / 656e-9 = 3.03018293e-19 = 3.03e-19 J

4 0
3 years ago
What is the definition of ecosystem?
dimaraw [331]

Answer:

A place where organic and non organic materials interact to make a living space

7 0
3 years ago
What are the first three overtones of a bassoon that has a fundamental frequency of 90.0 Hz? It is open at both ends. (The overt
vekshin1

Answer:

f_{2}=180Hz,f_{3}=270Hz,f_{4}=360Hz\\

Explanation:

Given data

Frequency f=90 Hz

To find

First three overtones of bassoon

Solution

The fundamental frequency of bassoon is found by substituting n=1 in below equation

f=v/λ=nv/2L

f_{1}=v/2L

The first overtone of bassoon is found by substituting n=2

So

f_{2}=2v/2L\\f_{2}=2(v/2L)\\as \\f_{1}=v/2L\\So\\f_{2}=2f_{1}\\f_{2}=2(90Hz)\\f_{2}=180Hz

The second overtone of bassoon is found by substituting n=3

So

f_{3}=3v/2L\\f_{3}=3(v/2L)\\as \\f_{1}=v/2L\\So\\f_{3}=3f_{1}\\f_{3}=3(90Hz)\\f_{3}=270Hz

The third overtone of bassoon is found by substituting n=4

So

f_{4}=4v/2L\\f_{4}=4(v/2L)\\as \\f_{1}=v/2L\\So\\f_{4}=4f_{1}\\f_{4}=4(90Hz)\\f_{4}=360Hz

5 0
4 years ago
an ice Puck travels 18 m in 3 S before it slides into the goal what is the speed of the traveling puck ​
DiKsa [7]

Answer:

\boxed {\boxed {\sf 6 \ meters \ per \ second}}

Explanation:

Speed can be found by dividing the distance by the time.

s=\frac{d}{t}

The distance is 18 meters and the time is 3 seconds.

d= 18 \ m \\t= 3 \ s\\

Substitute the values into the formula.

s=\frac{18 \ m }{ 3 \ s }

Divide.

s= 6 \ m/s

The speed of the puck is <u>6 meters per second.</u>

4 0
3 years ago
Read 2 more answers
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