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Verdich [7]
4 years ago
9

Mars completes one orbit around the Sun in approximately two Earth years. Mars orbits at an average distance to the Sun of about

1.5 AU, and Mars' mass is about 1/10 of the Earth's mass. Therefore Mars' orbital speed is _____ the orbital speed of the Earth.
Physics
1 answer:
satela [25.4K]4 years ago
3 0

Answer:

about 0.8 times

Explanation: MARS is a planet named after a Roman God of War, it is the fourth planet from the sun and the Second smallest planet following Mercury.

The orbital Speed of a planet is the speed with which the planet uses to completely go round the Sun.

The orbital Speed of the Earth is 29.78kilmeters per Second.

The orbital Speed of Mar is 0.8*29.78kilometers per second/1

=23.824kilmeters per second.

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Two stretched copper wires both experience the same stress. The first wire has a radius of 3.9×10-3 m and is subject to a stretc
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The stretching force acting on the second wire, given the data is 588 N

<h3>Data obtained from the question</h3>
  • Radius of fist wire (r₁) = 3.9×10⁻³ m
  • Force of first wire (F₁) = 450 N
  • Radius of second wire (r₂) = 5.1×10⁻³ m
  • Force of second wire (F₂) =?

<h3>How to determine the force of the second wire</h3>

F₁ / r₁ = F₂ / r₂

450 / 3.9×10⁻³ = F₂ / 5.1×10⁻³

cross multiply

3.9×10⁻³ × F₂ = 450 × 5.1×10⁻³

Divide both side by 3.9×10⁻³

F₂ = (450 × 5.1×10⁻³) / 3.9×10⁻³

F₂ = 588 N

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How do spectroscopes help with studying of distance stars?
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Human cell has 46 chromosomes. At the end of mitosis, there are two cells, each with 46 chromosomes, for a total of 92 chromosom
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A coil of wire containing N turns is in an external magnetic field that is perpendicular to the plane of the coil and it steadil
krok68 [10]

Answer:

The Resultant Induced Emf in coil is 4∈.

Explanation:

Given that,

A coil of wire containing having N turns in an External magnetic Field that is perpendicular to the plane of the coil which is steadily changing. An Emf (∈) is induced in the coil.

To find :-

find the induced Emf if rate of change of the magnetic field and the number of turns in the coil are Doubled (but nothing else changes).

So,

   Emf induced in the coil represented by formula

                          ∈  =   -N\frac{d\phi}{dt}                                  ...................(1)

                                          Where:

                                                    .   \phi = BAcos\theta     { B is magnetic field }

                                                                                 {A is cross-sectional area}

                                                    .  N = No. of turns in coil.

                                                    .  \frac{d\phi}{dt} = Rate change of induced Emf.

Here,

Considering the case :-

                                    N1 = 2N  &      \frac{d\phi1}{dt} = 2\frac{d\phi}{dt}

Putting these value in the equation (1) and finding the  new emf induced (∈1)

                           

                                      ∈1 =-N1\times\frac{d\phi1}{dt}

                                      ∈1 =-2N\times2\frac{d\phi}{dt}

                                       ∈1 =4 [-N\times\frac{d\phi}{dt}]

                                        ∈1 = 4∈             ...............{from Equation (1)}      

Hence,

The Resultant Induced Emf in coil is 4∈.        

                           

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4 years ago
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