The spin-drier of a washing machine revolving at 900.RPM slows down uniformly to 300.RPM while making 60. revolutions. Find the

Question

3 years ago

5

angular acceleration and the time required to turn through these 60. revolutions.

1 answer:

jeyben [28] · Answer 1 · 2022-07-28T12:24:08+03:00

<h2>Answer:</h2>

<u>Acceleration is </u><u>-10.57 rad/s² </u>

<u>Time is </u><u>6 seconds</u>

<h2>Explanation:</h2><h3>a) </h3>

u=900rpm= 94.248 rad/s

v =300rpm= 31.416 rad/s

s=60 revolutions= 377 rad

v²= u²+ 2as

31.416² = 94.248²+ 2 * a * 377

a = v²-u² / 2s

a= -10.57 rad/s²

Using 1st equation of motion

v-u/a = t

Putting the values

t = (31.4 - 94.2)/-10.57

t = 6 seconds