Let us convert the percentages to decimal format first.. so 5% is just 5/100 or 0.05 and 15% is just 15/100 or 0.15

so hmmm, so, let's say it needs "x" amount and "y" amount of each respectively, so, whatever "x" and "y" are, they must add up to 100, and whatever their concentration is, must add up to what the mixture yields

thus

$\bf \begin{array}{lccclll}
&amount&concentration&
\begin{array}{llll}
concentrated\\
amount
\end{array}\\
&-----&-------&-------\\
\textit{5\% alloy}&x&0.05&0.05x\\
\textit{30\% alloy}&y&0.30&0.3y\\
-----&-----&-------&-------\\
mixture&100&0.15&15
\end{array}
\\\\\\
\begin{cases}
x+y=100\implies \boxed{y}=100-x\\
0.05x+0.3y=15\\
----------\\
0.5x+0.3\left( \boxed{100-x} \right)=15
\end{cases}$

solve for "x"

what's "y"? well, y = 100 - x

4 0

3 years ago

In her last basketball game, Carla scored 46 points. In the current game, she has scored 24 points so far. How many more two-poi

KatRina [158]

Answer:

Carla needs to make at least 11 two-pointer shots in the surrent game

Step-by-step explanation:

The first thing we can do is to find the difference between the number of points that Carla scored in her first game and her second game.

This will be 46 - 24 = 22 points difference

Carla needs to make a certain number of two-pointers to get at least the same score she had in her previous game.

We can get this number of two-pointers that needed to be made by dividing the difference in scores by 2

i.e number of two-pointer shots = 22/2 =11 shots

Therefore, Carla needs to make at least 11 two-pointer shots to be able to get the same score in her current game.

8 0

3 years ago