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3 years ago

When the particles of two objects have the same average kinetic energy, what do we know about those objects?

Chemistry

1 answer:

Dmitriy789 [7]3 years ago

3 0

That they both will be the same average kinetic energy

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3 years ago

For each of the following choose the variable that will be more favorable in solution formation. A) Weak or Strong Solvent inter

Deffense [45]

Based on factors affecting solution formation;

Strong solvent-solute intermolecular forces favors solution formation.
Increase in entropy favours solution formation
Decrease in enthalpy favours solution formation

<h3>What is a solution?</h3>

A solution is a substance formed when a substance known as solute dissolves in another substance know as solvent.

Factors that affect solution formation include:

strength of intermolecular forces between solute and solvent
entropy
enthalpy

Strong solvent-solute intermolecular forces favors solution formation.

Increase in entropy favours solution formation

Decrease in enthalpy favours solution formation.

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6 0

2 years ago

A tablet of Pain Be Gone Aspirin, which had a mass of 1.213 g, was pulverized and 1.159 g were dissolved in 10.0 mL of ethyl alc

Elan Coil [88]

Answer:

a. Moles of $NaOH$ = 0.001643 moles

b. 0.296 g

c. 0.3098 g

d. Not acceptable

Explanation:

Considering:

$Molarity=\frac{Moles\ of\ solute}{Volume\ of\ the\ solution}$

Or,

$Moles =Molarity \times {Volume\ of\ the\ solution}$

Given :

For $NaOH$ :

Molarity = 0.1052 M

Volume = 15.62 mL

The conversion of mL to L is shown below:

1 mL = 10⁻³ L

Thus, volume = 15.62×10⁻³ L

Thus, moles of $NaOH$ :

$Moles=0.1052 \times {15.62\times 10^{-3}}\ moles$

Moles of $NaOH$ = 0.001643 moles

The reaction of NaOH with the acetylsalicylic acid is in the ratio of 1:1.

Thus, Moles of NaOH = Moles of acetylsalicylic acid = 0.001643 moles

Molar mass of acetylsalicylic acid = 180.16 g/mol

The formula for the calculation of moles is shown below:

$moles = \frac{Mass\ taken}{Molar\ mass}$

Thus,

Mass = Moles * Molar mass = 0.001643 moles * 180.16 g/mol = 0.296 g

1.159 g of sample contains 0.296 g of acetylsalicylic acid

1.213 g of sample contains $\frac{0.296}{1.159}\times 1.213$ g of acetylsalicylic acid

Mass of acetylsalicylic acid = 0.3098 g = 309.8 mg

d. Sample contains = 309.8 mg

Manufacturer claiming = 315 mg to 335 mg

Thus , it is not acceptable.

5 0

3 years ago