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2 years ago

How many grams of co2 are in 13 mol of the compound?

2 answers:

7 0

572.13 g

Here are the givens:
n=13 mol
M=44.01 g/mol (12.01 C + 2(16.00) O)

With the formula n=m/M, we can re-arrange it to m=nxM

Subbing in the values:

m=13 x 44.01
= 572.13

Nataly_w [17]2 years ago

6 0

The answer is <span>572.1235 grams of co2</span>

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What is the word that means "these break food into pieces

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Your digestive system

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2 years ago

A solution is made by dissolving 58.125 g of sample of an unknown, nonelectrolyte compound in water. The mass of the solution is

e-lub [12.9K]

Answer:

molecular weight (Mb) = 0.42 g/mol

Explanation:

mass sample (solute) (wb) = 58.125 g

mass sln = 750.0 g = mass solute + mass solvent

∴ solute (b) unknown nonelectrolyte compound

∴ solvent (a): water

⇒ mb = mol solute/Kg solvent (nb/wa)

boiling point:

ΔT = K*mb = 100.220°C ≅ 373.22 K

∴ K water = 1.86 K.Kg/mol

⇒ Mb = ? (molecular weight) (wb/nb)

⇒ mb = ΔT / K

⇒ mb = (373.22 K) / (1.86 K.Kg/mol)

⇒ mb = 200.656 mol/Kg

∴ mass solvent = 750.0 g - 58.125 g = 691.875 g = 0.692 Kg

moles solute:

⇒ nb = (200.656 mol/Kg)*(0.692 Kg) = 138.83 mol solute

molecular weight:

⇒ Mb = (58.125 g)/(138.83 mol) = 0.42 g/mol

8 0

2 years ago

The density of ice is 917 kg/m3. The density of salt water is 1029 kg/m3. A mass of ice is 2.55 x 1013 kg. Calculate the volume

Ksju [112]

Answer:

Volume of salt water, $V_{sw} = 247.74 km^3$

Explanation:

Density of Ice, $\rho_{ice} = 917 kg/m^3$

Density of salt water, $\rho_{sw} = 1029 kg/m^3$

Volume of ice, $V_{ice} = 278 km^3$

Volume of salt water, $V_{sw} = ?$

Mass = Density * Volume

Mass of Ice, $m_{ice} = \rho_{ice}V_{ice}$

Mass of Salt water, $m_{sw} = \rho_{sw}V_{sw}$

Since , $m_{ice} = m_{sw}$

$\rho_{ice}V_{ice} = \rho_{sw}V_{sw}\\\\(917*278) = (1029*V_{sw})\\\\V_{sw} = \frac{254926}{1029} \\\\V_{sw} = 247.74 km^3$

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3 years ago

A marathon covers a distance of 26.2 miles. If 1 mile is equivalent to exactly 1760 yards, what is the distance of the race in y

Contact [7]

Both mile and yard are units of distance thus they are inter convertible.

Distance covered in a marathon is 26.2 miles.

Since, 1 mile=1760 yards

Thus, distance can be converted into yards using the following conversion factor:

$\frac{1760 yards}{1 mile}$

Thus, distance covered in marathon in yard will be:

$d=26.2 mile(\frac{1760 yards}{1 mile})=46112 yards$

Therefore, distance of the race is 46112 yards.

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3 years ago

How many moles of hcl are required to make 500 ml of a 3.0 mol/l solution of hcl?

LiRa [457]

Answer:

1.5 moles

Explanation:

To find the number of moles of HCl in 500 mL of a 3 M solution of HCl, we consider moles in 1 liter/ 1000 mL.

3 moles HCl is contained in 1000 mL

x moles is HCl is contained in 500 mL

$= \frac{3 \: \times \: 500}{1000} \: moles \\ = 1.5 \: moles$

Hence the number of moles of HCl in 500 mL is 1.5 moles.

8 0

1 year ago