Answer:
Q (heat) = S * m * (T2 - T1) where Q is heat gained (loss), S the specific heat capacity of the substance and T2, T1 are the final and initial temps
Q = .215 cal / (g deg C) * 5 g * (20 - 80) deg C = -64.5 cal
Since the question specifies the heat emitted, then 64.5 cal is the
heat emitted (loss).
Answer:

Explanation:
Acceleration can be found by dividing the change in velocity by the time.
(<em>v </em>is the final velocity, <em>u</em> is the initial velocity, <em>t </em>is the time).
The velocity increased from 22 m/s to 236 m/s in 5 seconds. Therefore:

Substitute the values into the formula.

Subtract in the numerator.

Divide.

The acceleration of the object is <u>42.8 meters per square second.</u>
Answer:
The answer is below
Explanation:
Given that f(x) = x√3.
A function can be vertically stretched or compressed by multiplying it by a positive constant. If the constant is greater than 1, it is vertically stretched and if the constant is less than 1 it is vertically compressed.
If a function f(x) = x is compressed or stretched by a constant a, then the new function g(x) = a f(x)
If a function f(x) = x is translated a units down, then the new function g(x) = f(x) - a
If a function f(x) = x is translated a units left, then the new function g(x) = f(x-a)
If f(x) = x√3 is compressed vertically by a factor of 1/3. The new function is

If it is then translated 3 units left and 7 units down, the transformed function g(x) is:

Its A according to Ed Genuity