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vodomira [7]
3 years ago
11

7 times a number equals 3 less than 5 times that number. what is the number?

Mathematics
1 answer:
inessss [21]3 years ago
5 0

First the equation would look like this:

7n = 5n - 3

7n - 5n = 5n - 5n - 3   -Subtract 5n from both sides.  Which gives you...

2n = -3      

2n/2 = -3/2          -Divide both sides by 2

n = -1.5

Hope this helps!

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A cylinder has a circular base with a diameter of 12 ft the height of the cylinder is 4 feet what is the volume of the cylinder
Murrr4er [49]

Answer:

452\ ft^{3}

Step-by-step explanation:

we know that

The volume of a cylinder is equal to

V=\pi r^{2} h

we have

r=12/2=6\ ft ----> the radius is half the diameter

h=4\ ft

substitute the values

V=(3.14)(6^{2})(4)=452\ ft^{3}

5 0
4 years ago
A 2-gallon bottle of fabric softener costs $16.64. What is the price per cup?
Burka [1]

Answer:

each cup would cost $0.52

Step-by-step explanation:

there are 16 cups in 1 gallon so you multiply that by two. Then you have 32 so you divide 16.64 by 32 and you end up with 0.52.   hope this helped :))

Tell me I got this wrong

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2 years ago
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Bad White [126]

Answer:

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Step-by-step explanation:

5 0
3 years ago
Suppose that the function​
Dafna11 [192]

Answer:

<em>(</em><em>f-g</em><em>)</em><em>(</em><em>x</em><em>)</em><em>=</em><em> </em><em>-3x</em><em>^</em><em>3</em><em> </em><em>+</em><em> </em><em>x</em><em>^</em><em>2</em><em> </em><em>+</em><em> </em><em>6x</em>

<em>(</em><em>f</em><em>+</em><em>g</em><em>)</em><em>(</em><em>×</em><em>)</em><em>=</em><em> </em><em>3x</em><em>^</em><em>3</em><em> </em><em>+</em><em> </em><em>x</em><em>^</em><em>2</em><em> </em><em>+</em><em> </em><em>6x</em>

<em>(</em><em>f</em><em>•</em><em>g</em><em>)</em><em>(</em><em>2</em><em>)</em><em>=</em><em> </em><em>6x</em><em>^</em><em>3</em><em> </em><em>+</em><em> </em><em>36x</em><em>^</em><em>3</em>

Step-by-step explanation:

I hope that helps

5 0
3 years ago
Can someone solve this with steps cause idk how to solve the radicals
IceJOKER [234]
\bf 343^{\frac{2}{3}}+36^{\frac{1}{2}}-256^{\frac{3}{4}}\qquad \begin{cases}&#10;343=7\cdot 7\cdot 7\\&#10;\qquad 7^3\\&#10;36=6\cdot 6\\&#10;\qquad 6^2\\&#10;256=4\cdot 4\cdot 4\cdot 4\\&#10;\qquad 4^4&#10;\end{cases}\\\\\\ (7^3)^{\frac{2}{3}}+(6^2)^{\frac{1}{2}}-(4^4)^{\frac{3}{4}}&#10;\\\\\\&#10;\sqrt[3]{(7^3)^2}+\sqrt[2]{(6^2)^1}-\sqrt[4]{(4^4)^3}\implies \sqrt[3]{(7^2)^3}+\sqrt[2]{(6^1)^2}-\sqrt[4]{(4^3)^4}&#10;\\\\\\&#10;7^2+6-4^3\implies 49+6-64\implies -9


to see what you can take out of the radical, you can always do a quick "prime factoring" of the values, that way you can break it in factors to see who is what.
8 0
3 years ago
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