The question is incomplete. Here is the complete question.
Find the measurements (the lenght L and the width W) of an inscribed rectangle under the line y = -
x + 3 with the 1st quadrant of the x & y coordinate system such that the area is maximum. Also, find that maximum area. To get full credit, you must draw the picture of the problem and label the length and the width in terms of x and y.
Answer: L = 1; W = 9/4; A = 2.25;
Step-by-step explanation: The rectangle is under a straight line. Area of a rectangle is given by A = L*W. To determine the maximum area:
A = x.y
A = x(-
)
A = -
To maximize, we have to differentiate the equation:
=
(-
)
= -3x + 3
The critical point is:
= 0
-3x + 3 = 0
x = 1
Substituing:
y = -
x + 3
y = -
.1 + 3
y = 9/4
So, the measurements are x = L = 1 and y = W = 9/4
The maximum area is:
A = 1 . 9/4
A = 9/4
A = 2.25
Answer:
836
Step-by-step explanation:
4 times 19 times 11
Answer:
the chances of rolling a 3 are 1/6
the changes of not doing it is 5/6
The answer to your question is b.
Answer:

Step-by-step explanation:
First, we need to isolate
by taking it common from both terms on the right:

Now, since we want
in terms of the other variables, we can divide the left hand side (A) by whatever is multiplied with
on the right hand side. Then we will have an expression for
. Shown below:

This is the xpression for 