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Paul [167]
3 years ago
9

When the pressure that a gas exerts on a sealed container changes from 22.5 psi to ? psi, the temperature changes from 110 degre

es celcius to 65.0 degrees celcius?
Chemistry
1 answer:
natta225 [31]3 years ago
8 0
Using Gay-Lussac's Law, pressure is proportional to (absolute) temperature in Kelvin. We first convert the temperature values to Kelvin: 110 C = 383.15 K, while 65 C = 338.15 K.
P1/T1 = P2/T2
22.5/383.15 = P2/338.15
P2 = 19.9 psi
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consider the reaction of hydrogen and oxygen producing water. If 24.6 g of water is produced and 2.9 g of hydrogen is used, how
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Considering the reaction of hydrogen and oxygen to produce water.  If 24.6 g of water is produced and 2.9 g of hydrogen is used, the amount of oxygen needed is 21.87 grams

The best way to solve this question is to write out the reaction between hydrogen and oxygen that resulted in the formation of water.

So, we have:

\mathbf{ 2 H_2{(g)} + O_2{(g)} \to 2H_2O_{(l)}}

From the above reaction;

2 moles of hydrogen gas reacted with 1 mole of oxygen to produce 2 moles of water.

If;

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We can deduce that since 1 mole of O₂ produced 2 moles of H₂O;

Thus, 32 grams of O₂ is needed to produce 36 grams of H₂O.

∴

To produce, 24.6 grams of H₂O, we have:

\mathbf{=\Big(\dfrac{32 \times 24.6 }{36}\Big) grams }

= 21.87 grams of oxygen.

Therefore, we can conclude that the amount of oxygen needed is 21.87 grams.

Learn more about chemical reactions here:

brainly.com/question/1689737?referrer=searchResults

5 0
3 years ago
Two more substances put together but each retaining their own identity is a
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4 years ago
What does the law of convservation of matter show?​
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The law of conservation of energy states that energy is never created or destroyed only converted.
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4 years ago
Assume the alveolar radii are 0.05 and 0.07 mm towards the end of exhalation. Knowing that air flows from high to low pressures,
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Answer:

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Explanation:

Using Laplace's law of surface tension:

P=\frac{2T}{r}

where:

P = pressure

T = surface tension

r = radius

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P =  \frac{2*25mN/m}{0.07*10^{-2}m}

P = 0.714 mN/m^2

In the smaller alveoli with radius 0.05 mm = 0.05 * 10^{-2} m; we have:

P = \frac{2*25mN/m}{0.05*10^-2m}

P = 1.00 mN/m^2

The pressure difference can now be calculate as follows:

Pressure difference = (1.00 - 0.714)mN/m^2

Pressure difference = 0.286 mN/m^2

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3 years ago
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a) negative; increases; hidden
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