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mixer [17]
3 years ago
15

Please help on this one?

Physics
1 answer:
Rufina [12.5K]3 years ago
3 0

Answer

D. The acceleration vector of the planet points towards the center of the circle.

Explanation

For planetary motion , the velocity vector is always in a direction that is tangential to the direction of motion, not towards the center. Even though the speed of the planet may stay constant, it's velocity changes because it is constantly changing it's direction.

The centripetal force, which in this case is the force of gravity always points in the direction of the the center. The acceleration  vector always points in the direction of the of the center of the circle just like the centripetal force.

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You have landed on an unknown planet, newtonia, and want to know what objects will weigh there. you find that when a certain too
AleksandrR [38]
Refer to the diagram shown.

Because the surface is frictionless, the resistive for, R, is zero.

Let m = the mass of the object.
Let a =  acceleration due to the applied force.
Therefore
12.7 N = (m kg)*(a m/s²)
a = 12.7/m  m/s²

The object travels  16.1 m in 2.5 s, starting from rest. Therefore
16.1 N = (1/2)*(12.7/m m/s²)*(2.5 s)² = 39.6875/m  N
m = 16.1/39.6875 = 0.4057 kg

For freefall, let g =  acceleration due to gravity.
The time to fall from 10.3 m is 2.88 s, therefore
10.3 m = (1/2)*(g m/s²)*(2.88 s)² = 4.1472g m
g = 10.3/4.1472 = 2.484 m/s²

Answer:
The gravitational acceleration on the planet is 2.5 m/s² (nearest tenth)


3 0
3 years ago
A ball with a weight of 0.5 N is submerged under water and then released. There is a net force of 5 N upwards. what is the buoya
Natasha2012 [34]

Answer:

4.5 N upward

Explanation:

You take the net force and subtract it from the weight

~DjMia~

6 0
3 years ago
A cue ball has a mass of 0.5 kg. During a game of pool, the cue ball is struck and now has a velocity of 3 . When it strikes a s
photoshop1234 [79]

Answer: 3 m/s

Explanation:

We can solve the problem by using the law of conservation of momentum: during the collision between the two balls, the total momentum of the system before the collision and after the collision must be conserved:

p_i = p_f

The total momentum before the collision is given only by the cue ball, since the solid ball is initially at rest, therefore

p_i = m_c u_c = (0.5 kg)(3 m/s)=1.5 kg m/s

So, the final total momentum will also be

p_f = 1.5 kg m/s

And the total momentum after the collision is given only by the solid ball, since the cue ball is now at rest, therefore:

p_f = m_s v_s

from which we find the velocity of the solid ball

v_s = \frac{p_f}{m_s}=\frac{1.5 kg m/s}{0.5 kg}=3 m/s

8 0
3 years ago
Read 2 more answers
How much total surface of the moon is illuminated by the sun when it is at quarter phase?
alex41 [277]
50% of the moon is always illuminated, however during it's quarter phase means that we only see a quarter of what's really lit up. So it LOOKS like the moon is only 25% lit and 75% dark, it's truly 50/50. We only see that 25% since we can see it from one angle.
6 0
3 years ago
A box has a mass of 150kg and the surface area of the bottom of the box is :
charle [14.2K]

Answer:

Pressure = 100 Pascals

Explanation:

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