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serg [7]
3 years ago
15

How much total surface of the moon is illuminated by the sun when it is at quarter phase?

Physics
1 answer:
alex41 [277]3 years ago
6 0
50% of the moon is always illuminated, however during it's quarter phase means that we only see a quarter of what's really lit up. So it LOOKS like the moon is only 25% lit and 75% dark, it's truly 50/50. We only see that 25% since we can see it from one angle.
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Help me please thank you !
son4ous [18]

Answer:

one is photosynthesis ik

3 0
3 years ago
Part a consider a bird that flies at an average speed of 10.7 m/s and releases energy from its body fat reserves at an average r
Alex787 [66]
<span>436 km The conversion factor between kilocalorie/hour and watts is 1.163 (1 kcal/hr = 1.163 watt). So let's convert the energy consumption of the bird from watts to kcal/hr 3.7 w / 1.163 w hr/kcal = 3.18 kcal /hr 1 gram of fat has 9 kcal, so the total number of kcals consumed will be 4 * 9 = 36. So the bird can fly for 36/3.18 = 11.32 hours The distance traveled will be 11.32 h * 3600 s/h * 10.7 m/s / 1000 m/km = 436 km</span>
5 0
3 years ago
An astronaut stands by the rim of a crater on the moon, where the acceleration of gravity is 1.62 m/. To determine the depth of
leva [86]

Answer;

=32.15 meters

Explanation;

Use the formula  

s= ut+ 0.5 a (t)^2 to find out 's'  

where s= distance traveled  

u=initial velocity which is zero in this case  

t= time taken to travel 's' distance  

a=acceleration (due to gravity on moon i.e 1.62 m/s^2 )  

Therefore;

S = 0.5 * 1.62 * 6.3 * 6.3

    = 32.1489 meters

Thus; the crater is 32.15 meters deep.

3 0
3 years ago
Sally Sizzle builds a circuit by connecting three resistors in parallel with a 9V battery. The current in this circuit is 3.6 am
Andru [333]

Then answer is C 9 ohms

7 0
3 years ago
Read 2 more answers
A man with a weight of 100 N is located
valentina_108 [34]

Answer:

Given,

  mass of man = 100 N = 10 kg

   height = h = 25m

   since the man does not move anything with his force, work done by him is zero

   work done on the man = gain in potential energy

   P.E=mgh

   P.E=10×9.8×25

  P.E=2.45KJ

Explanation:

so, potential energy gained by man is 2.45 KJ

5 0
2 years ago
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