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Ulleksa [173]
3 years ago
13

2 What is the gram-formula mass of Ca(OH)2?

Chemistry
1 answer:
Verizon [17]3 years ago
7 0

Answer:

<em><u>The</u></em><em><u> </u></em><em><u>correct</u></em><em><u> </u></em><em><u>Answer</u></em><em><u> </u></em><em><u>is</u></em><em><u> </u></em><em><u>Number</u></em><em><u> </u></em><em><u>3</u></em><em><u> </u></em><em><u>the</u></em><em><u> </u></em><em><u>7</u></em><em><u>4</u></em><em><u> </u></em><em><u>g</u></em><em><u> </u></em><em><u>per</u></em><em><u> </u></em><em><u>mole</u></em><em><u> </u></em><em><u>.</u></em><em><u>.</u></em><em><u>.</u></em>

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A balloon filled with 6.0 MLS of air at a pressure of 15 PSI. when placed into a bell jar, the pressure decreased to 2.4 PSI. wh
lyudmila [28]

Answer:

2.6

Explanation:

2.6

5 0
2 years ago
Predict the whether the following reactions are possible or not.
vova2212 [387]

Answer:

1. No

2. No

3. Yes

4. No

5. Yes

6. No

Explanation:

Use the reactivity series. If the element is above it, it is more reactive. More reactive elements can displace less reactive elements from their compounds.

5 0
3 years ago
Name the two subatomic particles found in the nucleus.
Vesna [10]

i can think of 3 subatomic particles found in a nucleus protons, neutrons, and electrons

6 0
2 years ago
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In the reaction of a carbonyl compound with silver cyanide, the lone pair of electrons on the nitrogen are the one that attack t
never [62]

Answer:

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3 0
2 years ago
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Determine whether a precipitate will form when 0.96g of Na2CO3 is combined with 0.20g BaBr2 in a 10 L solution.
Mashcka [7]

Answer:

Qsp > Ksp, BaCO3 will precipitate

Explanation:

The equation of the reaction is;

Na2CO3 + BaBr2 -------> 2NaBr + BaCO3

Since BaCO3 may form a precipitate we can determine the Qsp of the system.

Number of moles of Na2CO3 = 0.96g/106 g/mol = 9.1 * 10^-3 moles

concentration of NaCO3 = number of moles/volume of solution = 9.1 * 10^-3 moles/10 L = 9.1 * 10^-4 M

Number of moles of BaBr2 = 0.20g/297 g/mol = 6.7 * 10^-4 moles

concentration of BaBr2 = 6.7 * 10^-4 moles/10 L = 6.7 * 10^-5 M

Hence;

[Ba^2+] = 6.7 * 10^-5 M

[CO3^2-] = 9.1 * 10^-4 M

Qsp = [6.7 * 10^-5] [9.1 * 10^-4]

Qsp = 6.1 * 10^-8

But, Ksp for BaCO3 is 5.1*10^-9.

Since Qsp > Ksp, BaCO3 will precipitate

3 0
3 years ago
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